我在 JavaScript 中使用 split() 方法得到了一個(gè)非常令人困惑的結(jié)果。var winning = "1234".split(" ");var entry1 = "23".split(" ");var entry2 = "123".split(" ");var entry3 = "55".split(" ");var entry4 = "8888".split(" ");var entry5 = "21".split(" ");var counter1, counter2, counter3, counter4, counter5;counter1 = 3;counter2 = 3;counter3 = 3;counter4 = 3;counter5 = 3;for(var i = entry1.length - 1; i >= 0; i--){    console.log(winning[counter1] + "===" + entry1[i]);    counter1 -= 1}for(var i = entry2.length - 1; i >= 0; i--){    console.log(winning[counter2] + "===" + entry2[i]);    counter2 -= 1}for(var i = entry3.length - 1; i >= 0; i--){    console.log(winning[counter3] + "===" + entry3[i]);    counter3 -= 1}for(var i = entry4.length - 1; i >= 0; i--){    console.log(winning[counter4] + "===" + entry4[i]);    counter4 -= 1}for(var i = entry5.length - 1; i >= 0; i--){    console.log(winning[counter5] + "===" + entry5[i]);    counter5 -= 1}當(dāng)我運(yùn)行這個(gè)簡(jiǎn)單的代碼時(shí)，使用 split 獲得的獲勝數(shù)組在任何索引中均未定義，但 split 方法生成的其他數(shù)組似乎工作正常。只是為什么？這是什么矛盾？