我嘗試使用此對(duì)象數(shù)組對(duì)對(duì)象數(shù)據(jù)進(jìn)行分組：var data = [     { IdUser: 8, Name: "John Smith", transferType: 'download', total: 6 },    { IdUser: 12, Name: "Jane Smith", transferType: 'download', total: 15 },    { IdUser: 11, Name: "Joe Smith", transferType: 'download', total: 20 },    { IdUser: 12, Name: "Jane Smith", transferType: 'upload', total: 7 },    { IdUser: 11, Name: "Joe Smith", transferType: 'upload', total: 16 },    { IdUser: 8, Name: "John Smith", transferType: 'upload', total: 12 } ];將所有對(duì)象的所需輸出格式獲取到新數(shù)組中：  [    {       IdUser: 8,       Name: 'John Smith',       download: [{ IdUser: 8, Name: "John Smith", transferType: 'download', total: 6}],       upload: [{ IdUser: 8, Name: "John Smith", transferType: 'upload', total: 12 }]    },    {        IdUser: 12,       Name: 'Jane Smith',       donwload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'download', total: 15 }],       upload: [{ IdUser: 12, Name: "Jane Smith", transferType: 'upload', total: 7 }]    },    {       IdUser: 11,       Name: 'Joe Smith',       download: [{ IdUser: 11, Name: "Joe Smith", transferType: 'download', total: 20 }],       upload: [{ IdUser: 11, Name: "Joe Smith", transferType: 'upload', total: 16 }]    }  ];我嘗試使用reduce函數(shù)，但它不是我得到的所需格式：data.reduce(function (a, b) {      a[b.Name] = a[b.Name] || [];         a[b.Name]["IdUser"] = b.IdUser;        a[b.Name][b.transferType] = a[b.Name][b.transferType] || [];           a[b.Name][b.transferType].push(b);      return a;    }, []);