我正在用 numpy 嘗試創(chuàng)建一個(gè) 3x3 矩陣。我想通過用戶輸入捕獲矩陣輸入，然后在用戶輸入時(shí)打印出矩陣。這就是我現(xiàn)在所擁有的，它會(huì)拋出一個(gè)ValueError: invalid literal for int() with base 10: 當(dāng)我運(yùn)行它時(shí)，我不知道為什么。我不會(huì)在任何地方輸入字母“a”，而只會(huì)輸入數(shù)字。def matrix(): row = int(3) column = int(3) matrix_input = [] print("Enter the entries in a single line (separated by space): ") for i in range(row): # A for loop for row entries entries = [] for j in range(column): # A for loop for column entries entries.append(int(input())) matrix_input.append(entries) # matrix_input = np.array(entries).reshape(row, column) print(matrix_input)目標(biāo)是讓用戶在三個(gè)單獨(dú)的行上輸入 3 個(gè)數(shù)字。例子：130304603然后，程序會(huì)按照用戶輸入的內(nèi)容以相同的格式準(zhǔn)確地輸入該內(nèi)容。130304603任何指導(dǎo)將不勝感激。謝謝
4 回答
搖曳的薔薇
TA貢獻(xiàn)1793條經(jīng)驗(yàn) 獲得超6個(gè)贊
現(xiàn)在，您的代碼分別要求每個(gè)元素。如果你輸入數(shù)字直到它像這樣結(jié)束
111
222
333
444
555
666
777
888
999
程序?qū)⒎祷?/p>
[[111, 222, 333], [444, 555, 666], [777, 888, 999]]
發(fā)生這種情況是因?yàn)閕nput()位于最內(nèi)層循環(huán)內(nèi)，因此被調(diào)用了 9 次。
因此，如果您想輸入所示的由空格分隔的值，您可以使用列表理解將其轉(zhuǎn)換為數(shù)字列表：
row = int(3)
matrix_input = []
print("Enter the entries in a single line (separated by space): ")
for i in range(row): # A for loop for row entries
matrix_input.append([int(k) for k in input().split(' ')])
for out in matrix_input:
print('{0} {1} {2}'.format(*out))
這將要求三個(gè)條目，這些條目沿空格分割并轉(zhuǎn)換為整數(shù)。如果你想要浮動(dòng)，你可以使用float(k)而不是int(k)。print 命令使用解包并返回行for ... in。
或者，您可以使用' '.join()，它更靈活：
for out in matrix_input:
print(' '.join([str(el) for el in out]))
這實(shí)際上是構(gòu)造矩陣的逆運(yùn)算。
大話西游666
TA貢獻(xiàn)1817條經(jīng)驗(yàn) 獲得超14個(gè)贊
def matrix():
row = int(3)
column = int(3)
matrix_input = []
print("Enter the entries in a single line (separated by space): ")
for i in range(row): # A for loop for row entries
ints =input()
entries = []
for a in ints:
entries.append(int(a))
matrix_input.append(entries)
for ele in matrix_input:
for d in ele:
print(d,end='')
print('')
matrix()
輸入：
Enter the entries in a single line (separated by space):
130
304
603
輸出：
130
304
603
弒天下
TA貢獻(xiàn)1818條經(jīng)驗(yàn) 獲得超8個(gè)贊
問題是您試圖將整個(gè)字符串（每個(gè) int 之間有空格的輸入）轉(zhuǎn)換為整數(shù)。
相反，您需要拆分輸入。見下文：
def matrix():
row = int(3)
column = int(3)
matrix_input = []
print("Enter the entries in a single line (separated by space): ")
input_str = input()
entries = []
entries.extend([int(x) for x in input_str.split(' ')])
for item in entries:
print(item)
Cats萌萌
TA貢獻(xiàn)1805條經(jīng)驗(yàn) 獲得超9個(gè)贊
這可以解決問題。
def matrix():
row = int(3)
column = int(3)
matrix_input = []
print("Enter the entries in a single line (separated by space): ")
for i in range(row): # A for loop for row entries
# ints = input().split()
while True:
ints = input().split()
if len(ints) == 3:
break
print("Invalid Input Received")
print("Enter the entries in a single line (separated by space): ")
entries = []
for a in ints:
entries.append(int(a))
matrix_input.append(entries)
print("Output")
for ele in matrix_input:
for d in ele:
print(d, end=' ')
print('')
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