對編碼和 Python 非常陌生。我試圖將計算結果限制為小數(shù)點后兩位，或者我想要的任意位數(shù)。通過 Google 發(fā)現(xiàn)了有關使用小數(shù)的信息，但我無法讓我的代碼正常工作。我從什么開始amount_per_day = amount_of_money/currency_amountprint("If you are going to spend " + str(amount_of_money) + " " + str(destination_currency) + " that means that you can spend up to " + str(amount_per_day) + " " + Home_currency + " per day to remain in budget.")我嘗試過的from decimal import Decimalamount_per_day = Decimal(amount_of_money/currency_amount)amount_per_day_to_two_decimal_places = round(amount_per_day,2)print("If you are going to spend " + str(amount_of_money) + " " + str(destination_currency) + " that means that you can spend up to " + str(amount_per_day) + " " + Home_currency + " per day to remain in budget.")結果如果您打算花費 2000.0 歐元，這意味著您每天最多可以花費 1818.181818181818016455508768558502197265625 英鎊以保持在預算之內。這些代碼可以工作，但我不需要小數(shù)點后 39 位的答案。
4 回答
倚天杖
TA貢獻1828條經(jīng)驗 獲得超3個贊
要四舍五入，您可以使用以下內容：
value = 1818.181818181818016455508768558502197265625 print(round(value, 2))
您可以使用以下內容來設置文本格式。
print('you can spend %.2f GBP per day' % value)
達令說
TA貢獻1821條經(jīng)驗 獲得超6個贊
一旦您計算出小數(shù)點后 39 位的 amount_per_day，您就可以使用內置函數(shù)“round”簡單地刪除它們
圓形的工作原理如下：round(float_num, num_of_decimals)
所以在你的情況下你會這樣做amount_per_day = round(amount_per_day, 2)
我還建議您將 print 語句中添加的所有令人討厭的字符串替換為 f 字符串，如下所示：
print(f"If you are going to spend {str(amount_of_money)}
{str(destination_currency)} that means that you can
spend up to {str(amount_per_day)} {Home_currency} per
day to remain in budget.")
它看起來更干凈而且實際上也更快
富國滬深
TA貢獻1790條經(jīng)驗 獲得超9個贊
Python 有一個內置函數(shù)round。文檔中對此進行了深入介紹。
因此，就您而言，您正在尋找的結果是round(amount_per_day, 2).?請注意，這會將輸出更改為小數(shù)點后兩位（因此將有效地截掉第二個小數(shù)點后的剩余部分），并且即使在最接近值之間的中間，也會四舍五入到最接近的偶數(shù)值。
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