我有一個如下所示的 df 。它包含每月 1-12 月的費(fèi)用。我想創(chuàng)建一個新列，其中包含每 12 行（第 1-12 個月）的成本總和的百分比。因此，它將獲取 12 行的總和并計算成本中值的百分比。我真的不知道從哪里開始。謝謝你的幫助！輸入：| Name | Month | Costs ||----------|--------|-------|| Painting | 1 | 1000 || Painting | 2 | 0 || Painting | 3 | 0 || Painting | 4 | 0 || Painting | 5 | 1000 || Painting | 6 | 0 || Painting | 7 | 0 || Painting | 8 | 0 || Painting | 9 | 1000 || Painting | 10 | 0 || Painting | 11 | 0 || Painting | 12 | 1000 || Repair | 1 | 0 || Repair | 2 | 0 || Repair | 3 | 0 || Repair | 4 | 2500 || Repair | 5 | 0 || Repair | 6 | 0 || Repair | 7 | 5000 || Repair | 8 | 0 || Repair | 9 | 0 || Repair | 10 | 2500 || Repair | 11 | 0 || Repair | 12 | 0 |想要的輸出：| Name | Period | Costs | Percentages ||----------|--------|-------|-------------|| Painting | 1 | 1000 | 25% || Painting | 2 | 0 | 0% || Painting | 3 | 0 | 0% || Painting | 4 | 0 | 0% || Painting | 5 | 1000 | 25% || Painting | 6 | 0 | 0% || Painting | 7 | 0 | 0% || Painting | 8 | 0 | 0% || Painting | 9 | 1000 | 25% || Painting | 10 | 0 | 0% || Painting | 11 | 0 | 0% || Painting | 12 | 1000 | 25% || Repair | 1 | 0 | 0% || Repair | 2 | 0 | 0% || Repair | 3 | 0 | 0% || Repair | 4 | 2500 | 25% || Repair | 5 | 0 | 0% || Repair | 6 | 0 | 0% || Repair | 7 | 5000 | 50% || Repair | 8 | 0 | 0% || Repair | 9 | 0 | 0% || Repair | 10 | 2500 | 25% || Repair | 11 | 0 | 0% || Repair | 12 | 0 | 0% |
1 回答
POPMUISE
TA貢獻(xiàn)1765條經(jīng)驗 獲得超5個贊
嘗試transform
df['PCT']=df['Costs']/df.groupby('Name')['Costs'].transform('sum')
df
Out[98]:
Name Month Costs PCT
0 Painting 1 1000 0.25
1 Painting 2 0 0.00
2 Painting 3 0 0.00
3 Painting 4 0 0.00
4 Painting 5 1000 0.25
5 Painting 6 0 0.00
6 Painting 7 0 0.00
7 Painting 8 0 0.00
8 Painting 9 1000 0.25
9 Painting 10 0 0.00
10 Painting 11 0 0.00
11 Painting 12 1000 0.25
12 Repair 1 0 0.00
13 Repair 2 0 0.00
14 Repair 3 0 0.00
15 Repair 4 2500 0.25
16 Repair 5 0 0.00
17 Repair 6 0 0.00
18 Repair 7 5000 0.50
19 Repair 8 0 0.00
20 Repair 9 0 0.00
21 Repair 10 2500 0.25
22 Repair 11 0 0.00
23 Repair 12 0 0.00
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