我正在嘗試使用 ajax 將文件和文本插入數(shù)據(jù)庫(kù)，但它不起作用。主要問(wèn)題是文件未插入數(shù)據(jù)庫(kù)這是我的代碼 <form id="descriptionsubmit" enctype = "multipart/form-data"> <textarea class="form-control" id="textarea-description" placeholder="Write Something"></textarea> <input type="file" name="upload-pic" id="upload-pic" class="inputfile" > <button type="submit" class="update-btn">Next</button></form>Ajax 同樣的警報(bào)（數(shù)據(jù)）沒(méi)有顯示任何內(nèi)容$(function(){ $('form#descriptionsubmit').on('submit', function (e) { e.preventDefault(); var file_data = $('#upload-pic').prop('files')[0]; var formData = new FormData(this); $.ajax({ method: "POST", url : "AJAXSubmitClientData.php", data :formData, dataType : "html", contentType: false, enctype: 'multipart/form-data', cache: false, processData:false, success:function(data) { alert(data); } });PHP代碼這里插入了描述但沒(méi)有插入文件if(isset($_POST['formData'])){$file = array( "name" => $_FILES['form_data']['name'], "tmp_name" => $_FILES['form_data']['tmp_name'] ); print_r($file);$fileinserted = $objMaster->imageinsert($file);$dataDescription = array( "description" => $_POST['description'], "projectProfile" => $fileinserted, ); echo $insertdata = $objMaster->updateJobPostTable($dataDescription,$_SESSION['lastinsertid']);echo 1;}圖像插入函數(shù) public function imageinsert($file, $path = "") { $fname = ""; $uploadpath = ""; if ($path == "") { $uploadpath = $this->upload1; } else { $uploadpath = $this->upload1 . $path . "/"; } $current_timestamp = $this->timeStamp(); $filename = basename($file['name']); $newname = $current_timestamp . $filename; if ((move_uploaded_file($file['tmp_name'], $uploadpath . $newname))) { $fname = $newname; } return $fname; }任何幫助表示贊賞
1 回答
臨摹微笑
TA貢獻(xiàn)1982條經(jīng)驗(yàn) 獲得超2個(gè)贊
HTML 頁(yè)面 :-
將button屬性值更改為type="button"而不是type="submit"&添加onclick事件屬性。
<form id="descriptionsubmit" action="" method="post" enctype = "multipart/form-data">
<textarea class="form-control" name="textarea-description" placeholder="Write Something"></textarea>
<input type="file" name="upload-pic" id="upload-pic" class="inputfile" >
<button type="button" onclick="addData()" class="update-btn">Next</button>
</form>
JS AJax 代碼：-
function addData() {
var formData = new FormData($('#descriptionsubmit')[0]);
formData.append('action', 'add');
$.ajax({
method: 'post',
processData: false,
contentType: false,
cache: false,
enctype: 'multipart/form-data',
url: 'AJAXSubmitClientData.php',
data: formData,
success:function(msg){
alert(msg);
}
});
}
AJAXSubmitClientData.php
<?php
include('dbconn.php');
if(isset($_POST["action"]) && $_POST["action"]=="add"){
echo $a = $_POST["textarea-description"];
echo $g = $_FILES["upload-pic"]["name"];
// insert code here.
}
?>
- 1 回答
- 0 關(guān)注
- 128 瀏覽
添加回答
舉報(bào)
0/150
提交
取消