我有一個(gè)字符串?dāng)?shù)組adrs[] = {    "BD Jules Ferry",    "Rue de Republique",    "Avenue de Julin"};我有一個(gè)名為“Address”的對(duì)象（為了簡(jiǎn)單起見，省略了 getter setter）public class Address{     adrsLine1 String;     adrsLine2 String;     adrsLine3 String;     postalCode String;}我想通過將數(shù)組中的每個(gè)字符串分配為 的參數(shù)來將其轉(zhuǎn)換adrs[]為。List<<Address>> addrsListadrsLine1Address一旦轉(zhuǎn)換后，我的每個(gè)地址對(duì)象addrsList就會(huì)像這樣，addrsList.get(0)將有 [BD Jules Ferry, null, null, null]addrsList.get(1)將有 [Rue de Republique, null, null, null]addrsList.get(2)將有 [Avenue de Julin, null, null, null]我使用Java 8，目前，我用它for loop來實(shí)現(xiàn)這一點(diǎn)，Java 8中有沒有捷徑或更有效的方法？示例代碼：private String[] AdrsArray = {"BD Jules Ferry", "Rue de Republique", "Avenue de Julin"};List<Address> addrsList = new ArrayList<>();for (String adrsLine : AdrsArray){    Address address = new ReturnAddress();    address.setAdrsLine1(adrsLine);    addrsList.add(address);} 輸出：Address address = addrsList.get(0); address.getAdrsLine1() //should have "BD Jules Ferry"address.getAdrsLine2() //should have nulladdress.getAdrsLine3() //should have nulladdress.getAdrsPostalCode() //should have null