當(dāng)我嘗試運行此代碼時，ValueError會出現(xiàn)一個暗指該函數(shù)的numRandom。我認(rèn)為 Python 可以將 int 的字符串表示形式傳遞給int.import tkinterimport randomwindow = tkinter.Tk()window.geometry('600x500')x = random.randint(1,300)remainingTime = TrueAttempts = 4def numRamdom(): global Attempts while Attempts > 0: numWritten = int(entryWriteNumber.get()) if numWritten > x: lblClue.configure(text = 'Its a bigger number') Attempts = Attempts -1 if numWritten < x: lblClue.configure(text = 'Its a smaller number') Attempts = Attempts -1 if numWritten == x: lblClue.configure(text = 'Congratulations ;)') remainingTime = False return remainingTime, countdown(0) if Attempts == 0: remainingTime = False return remainingTime, countdown(0), Attempts, gameOver()entryWriteNumber = tkinter.Entry(window)entryWriteNumber.grid(column = 0, row = 1, padx = 10, pady = 10)numRamdom()window.mainloop()
2 回答
qq_遁去的一_1
TA貢獻1725條經(jīng)驗 獲得超8個贊
問題是因為當(dāng)代碼運行時，它直接調(diào)用numRamdom()，也就是說，最初條目小部件是空的，并且它們使用這些空條目小部件運行它，因此出現(xiàn)錯誤。因此，只需分配一個按鈕和一個命令，例如：
b = tkinter.Button(root,text='Click me',command=numRamdom)
b.grid(row=1,column=0)
mainloop()請務(wù)必在之前、之后說這句話def numRamdom():。僅當(dāng)單擊按鈕時該按鈕才運行該功能。
或者，如果您想要無按鈕，請嘗試：
方法一：
root.after(5000,numRamdom) #after 5 sec it will execute function
但請記住，如果用戶在 5 秒內(nèi)沒有正確輸入，則會彈出一些錯誤。
方法2：
def numRamdom(event):
......
entryWriteNumber.bind('<Return>',numRamdom)
這樣，如果您在輸入小部件中按 Enter 鍵（輸入數(shù)據(jù)后），它將運行該功能。
希望這有幫助，如果有任何錯誤請告訴我。
一只萌萌小番薯
TA貢獻1795條經(jīng)驗 獲得超7個贊
這是一個基于您的代碼的完整工作示例。您的問題是嘗試在其中包含任何內(nèi)容之前轉(zhuǎn)換條目的內(nèi)容。要解決此問題，您可以添加一個調(diào)用命令的按鈕numRamdom()
import tkinter
import random
window = tkinter.Tk()
window.geometry('600x500')
x = random.randint(1,300)
remainingTime = True
Attempts = 4
def numRamdom():
global Attempts, lblClue, x
if Attempts > 0:
numWritten = int(entryWriteNumber.get())
if numWritten < x:
lblClue.configure(text = 'Its a bigger number')
Attempts = Attempts -1
elif numWritten > x:
lblClue.configure(text = 'Its a smaller number')
Attempts = Attempts -1
else:
lblClue.configure(text = 'Congratulations ;)')
remainingTime = False
#return remainingTime, countdown(0)
if Attempts == 0:
remainingTime = False
#return remainingTime, countdown(0), Attempts, gameOver()
else:
lblClue.configure(text = "You ran out of attempts!")
entryWriteNumber = tkinter.Entry(window)
entryWriteNumber.grid(column = 0, row = 1, padx = 10, pady = 10)
entryWriteButton = tkinter.Button(window, text = "Push me!", command = numRamdom)
entryWriteButton.grid(column = 1, row = 1)
lblClue = tkinter.Label(window)
lblClue.grid(row = 2, column = 1)
window.mainloop()
如果傳遞的值無法轉(zhuǎn)換為整數(shù)，您仍然會收到錯誤，但這很容易通過語句修復(fù)if。
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