我正在使用 blueimp jQuery 文件上傳作為文件上傳器。這是我的控制器代碼。public function savedocument() { $response = array('status' => 'failed', 'message' => 'Unknown reason'); $config = array(); $config['upload_path'] = 'upload path'; $config['allowed_types'] = 'gif|jpg|png|pdf|doc|docx'; $config['max_size'] = '20480'; $config['overwrite'] = FALSE; //var_dump($config); $this->load->library('upload', $config); $files = $_FILES; for($i=0; $i< count($_FILES['files']['name']); $i++) { $_FILES['files']['name']= $files['files']['name'][$i]; $_FILES['files']['type']= $files['files']['type'][$i]; $_FILES['files']['tmp_name']= $files['files']['tmp_name'][$i]; $_FILES['files']['error']= $files['files']['error'][$i]; $_FILES['files']['size']= $files['files']['size'][$i]; $this->upload->initialize($config); if (!$this->upload->do_upload('files')) { $response['message'] = $this->upload->display_errors(); } else { $file_details = $this->upload->do_upload('files'); $response['status'] = 'success'; $response['message'] = $file_details; } } }我得到打印 $file_details 的值為 bool(true)。上傳的文件名（即上傳庫(kù)分配的名稱）不起作用。我想獲取這些詳細(xì)信息。如何獲取它？如果有人知道請(qǐng)幫助。
1 回答
qq_笑_17
TA貢獻(xiàn)1818條經(jīng)驗(yàn) 獲得超7個(gè)贊
$this->upload->do_upload('files');true如果文件上傳正確則返回。你想要的可能是$this->upload->data()。另外，我建議更改文件名（不是必需的，但有助于調(diào)試）。下面是關(guān)于這個(gè)問(wèn)題的工作代碼 -
for($i = 0; $i < count($_FILES['files']['name']); $i++){
$_FILES['user_file']['name'] = $_FILES['files']['name'][$i];
$_FILES['user_file']['type'] = $_FILES['files']['type'][$i];
$_FILES['user_file']['tmp_name'] = $_FILES['files']['tmp_name'][$i];
$_FILES['user_file']['error'] = $_FILES['files']['error'][$i];
$_FILES['user_file']['size'] = $_FILES['files']['size'][$i];
$fileName = 'user_file';
}
$config['upload_path'] = 'your-path-here';
$config['allowed_types'] = 'gif|jpg|jpeg|png|GIF|JPG|PNG|JPEG';
$config['max_size'] = 6096;
$config['max_width'] = 1024;
$config['max_height'] = 768;
$config['encrypt_name'] = TRUE;
$this->load->library('upload', $config);
$this->upload->initialize($config);
$uploaded = $this->upload->do_upload($fileName);
if ( ! $uploaded ){
$error = array('error' => $this->upload->display_errors());
}else{
$upload_data = $this->upload->data(); // You'll get all the data of the uploaded file here.
$file = $upload_data['file_name'];
}
看看是否對(duì)你有幫助。
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