我有一系列餐廳，我需要根據(jù)以下規(guī)則計(jì)算每家餐廳的排名：到我的距離（公里）(weight=30)喜歡(weight=10)$restaurants = [ {name: "KFC", distance: 17, likes: 3}, {name: "Macdonalds", distance: 2, likes: 9}, {name: "Pizza Hut", distance: 9, likes: 12}, {name: "Burger King", distance: 14, likes: 17},];排名越高意味著這家餐廳離我很近，并且根據(jù)等式有更多的喜歡。等式應(yīng)該是什么？
1 回答
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TA貢獻(xiàn)1846條經(jīng)驗(yàn) 獲得超7個(gè)贊
這是解決您的問題的一種可能的解決方案。我們使用一個(gè)權(quán)重?cái)?shù)組，其鍵與餐廳數(shù)組中的鍵和值相匹配，如您的問題所示。請(qǐng)注意，對(duì)于距離，我們使用負(fù)值，因?yàn)槟Ｍ牟蛷d（距離值越小）排名越高。然后，我們可以根據(jù)每個(gè)權(quán)重的評(píng)分總和對(duì)餐廳數(shù)組進(jìn)行排序：
function get_rating($restaurant, $weights) {
$rating = 0;
foreach ($weights as $factor => $weight) {
$rating += $weight * $restaurant[$factor];
}
return $rating;
}
$weights = array('distance' => -30, 'likes' => 10);
usort($restaurants, function ($a, $b) use ($weights) {
return get_rating($b, $weights) - get_rating($a, $weights);
});
print_r($restaurants);
輸出：
Array
(
[0] => Array
(
[name] => Macdonalds
[distance] => 2
[likes] => 9
)
[1] => Array
(
[name] => Pizza Hut
[distance] => 9
[likes] => 12
)
[2] => Array
(
[name] => Burger King
[distance] => 14
[likes] => 17
)
[3] => Array
(
[name] => KFC
[distance] => 17
[likes] => 3
)
)
請(qǐng)注意，$restaurants您問題中的變量不是有效的 PHP 結(jié)構(gòu)；我假設(shè)你有一個(gè)關(guān)聯(lián)數(shù)組。
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