你好，我從 API 得到了這樣的結(jié)果：$data = ["1" => [ "book" => "Harry Potter", "artist" => array("David", "Emma"), "country" => [ ["description" => "Wander"], ["description" => "Magic"] ]],"2" => [ "book" => "Science book", "artist" => array("Artist 1", "Melanie Hudson"), "country" => [ ["description" => "Physics"], ["description" => "Albert Einstein"] ]],"3" => [ "book" => "Bible", "artist" => array("Artist 1", "Pedro"), "country" => [ ["description" => "Love"], ["description" => "Respect"] ]],];我正在做的是使用 PHP 在多維數(shù)組中部分搜索字符串值。當我搜索值（例如波特）時它正在工作book。但當涉及到artist和時country。我的代碼不再起作用了。搜索將返回所有匹配項。以下是我到目前為止所做的事情：function searchFor($haystack, $needle){$r = array();foreach($haystack as $key => $array) {$contains = false;foreach($array as $k => $value) { if (!is_array($value)) { if(stripos($value, $needle) !== false ) { $contains = true; } } else { searchFor($array['country'],$needle); } } if ($contains) { array_push($r,$array); } } return $r; }echo ("<pre>");print_r(searchFor($data,"Wander")); <--- Not working. but when I change it to Potter it will work.echo ("</pre>");任何關于如何改進我的代碼的想法將不勝感激。注意：我試圖減少 PHP 中許多循環(huán)和內(nèi)置函數(shù)的使用。我只是想要一個簡單但有效的解決方案。希望有人能分享一些想法。謝謝
2 回答
守著星空守著你
TA貢獻1799條經(jīng)驗 獲得超8個贊
您需要將遞歸調(diào)用的結(jié)果與searchFor您的 result 合并$r。在語句中嘗試以下else遞歸調(diào)用searchFor：
else {
$r = array_merge($r, searchFor($array['country'],$needle));
}
largeQ
TA貢獻2039條經(jīng)驗 獲得超8個贊
以下邏輯可能會幫助您：
$result = []; // $result is container for matches - filled by reference
$needle = 'Wander'; // the value we are looking for
recurse($data, $needle, $result);
function recurse($haystack = [], $needle = '', &$result) {
foreach($haystack as $key => $value) {
if(is_array($value)) {
recurse($value, $needle, $result);
} else {
if(strpos($value, $needle) !== false) {
$result[] = $value; // store match
}
}
}
}
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