我嘗試將一些 Scala 源代碼轉(zhuǎn)換為 Java 源代碼。但我面臨一些麻煩。以下是 Scala 源代碼。trait Reader { def read(name: String): String = { //some codes are here..... }}trait FileInputBase { def getFormat(path: String): String = { //some codes are here..... }}case class FileStreamInput(name: String, path: String) extends Reader with FileInputBase { def read(name: String): String = { //some codes are here..... } var format = getFormat("joseph") }我將這些 Scala 代碼轉(zhuǎn)換為 Java 源代碼，如下所示，class Reader { public String read(String name) { // some java codes are here }}interface FileInputBase { public String getFormat(String path) { // some java codes are here }}我做了java類(lèi)public class FileStreamInput extends Reader implements FileInputBase { ....}但這些Java代碼根本不起作用。我是 Scala 語(yǔ)言的初學(xué)者。
1 回答
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你可以嘗試這樣的事情：
public interface Reader {
default String read(String name) {
return "reading from " + name;
}
}
public interface FileInputBase {
default String getFormat(String path) {
return "Format of " + path;
}
}
public class FileStreamInput implements Reader, FileInputBase {
private String path;
private String name;
public FileStreamInput(String path, String name) {
super();
this.path = path;
this.name = name;
}
public String read(String name) {
return "FileStreamInput: reading from " + name;
}
public String getPath() {
return path;
}
public void setPath(String path) {
this.path = path;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getFormat() {
return getFormat(path);
}
public static void main(String[] args) {
FileStreamInput input = new FileStreamInput("Alice", "/home/alice");
System.out.println("format: " + input.getFormat());
}
}
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