這是代碼：dict1 = {"games" : ["football", "cricket"]}print(dict1)input1 = input("enter key : ")input2 = input("enter value : ")dict1[input1].pop(input2)它給出的輸出為：'games': ['football', 'cricket']}enter key : gamesenter value : footballTraceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 116, in <module> dict1[input1].pop(input2)TypeError: 'str' object cannot be interpreted as an integerProcess finished with exit code 1它與附加一起工作正常dict1[input1].append(input2)即使我嘗試使用 for 循環(huán)：for key, values in dict1.items(): values.pop(input2)它給出的錯(cuò)誤為：{'games': ['football', 'cricket']}enter key : gamesenter value : footballTraceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 113, in <module> values.pop(input2)TypeError: 'str' object cannot be interpreted as an integerProcess finished with exit code 1當(dāng)我使用 (int) 時(shí)：input2 = int(input("enter value : "))它給出的錯(cuò)誤為Traceback (most recent call last): File "C:/Users/fateo/PycharmProjects/pythonTuts/10Dictionary.py", line 110, in <module> input2 = int(input("enter value : "))ValueError: invalid literal for int() with base 10: 'football'我也用了deldel dict1[input2]它說(shuō)TypeError: 'str' object cannot be interpreted as an integer我不明白為什么它把它解釋為整數(shù)
3 回答
Smart貓小萌
TA貢獻(xiàn)1911條經(jīng)驗(yàn) 獲得超7個(gè)贊
不要使用pop嘗試這個(gè)代替。
dict1 = {"games" : ["football", "cricket"]}
print(dict1)
input1 =input("enter key : ")
input2 = input("enter value : ")
for value in dict1.values():
if (input2) in value:
value.remove(input2)
print(dict1)
猛跑小豬
TA貢獻(xiàn)1858條經(jīng)驗(yàn) 獲得超8個(gè)贊
對(duì)于 pop()，您應(yīng)該給出索引，而不是鍵。即使 del 語(yǔ)句也應(yīng)該與索引一起給出。使用remove()代替
慕萊塢森
TA貢獻(xiàn)1810條經(jīng)驗(yàn) 獲得超4個(gè)贊
您不能使用pop帶有字符串值作為參數(shù)的 on 列表。需要pop要?jiǎng)h除的元素的索引。
因?yàn)槟愕淖值渲挥幸粋€(gè)鍵，所以最簡(jiǎn)單的方法就是字典理解：
{k: [x for x in v if x != input2] for k, v in dict1.items() if k == input1}
..您的示例中的內(nèi)容如下所示：
dict1 = {"games" : ["football", "cricket"]}
print(dict1)
input1 = input("enter key : ")
input2 = input("enter value : ")
print({k: [x for x in v if x != input2] for k, v in dict1.items() if k == input1})
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