當用戶單擊下拉列表的所選項目時，我需要獲取子 id，并且人們告訴我，我需要在控制器和視圖之間傳遞數(shù)據(jù)多次，我找到一個 ajax 代碼將該 id 發(fā)布到控制器，但它返回 null。這是執(zhí)行此操作的正確方法嗎？我的看法 ：@using (Html.BeginForm()){<table class="table table-hover"> <tr> <td> @Html.Label("PersonalAd?") </td> <td>@Html.EditorFor(model => model.PersonalName)</td> </tr> <tr> <td> @Html.Label("Departman")</td> <td> @Html.EditorFor(model => model.PersonalDepartment)</td> </tr> <tr> <td>@Html.Label("IseGirisTarihi")</td> <td>@Html.EditorFor(model => model.IseGirisTarihi)</td> </tr> <tr> <td> @Html.DisplayNameFor(model => model.FormDetail.Form) </td> <td> @Html.DropDownListFor(model => model.FormDetail.FormId, Model.FormViewList) </td> </tr> <tr> <td> @Html.DisplayNameFor(model => model.FormDetail.CheckListType) </td> <td> @Html.DropDownListFor(model => model.FormDetail.CheckListTypeId, Model.checkLists, new {@id="Selection", @class = "drop-open" }) <td><button onclick="">Bolum Ekle</button></td> </tr> <tr> <td colspan="2" style="padding-top:40px;"> <input type="submit" value="Save" class="btn btn-info" /> </td> </tr></table><script src="~/Scripts/jquery-3.1.1.min.js"></script><script src="~/Content/js/open.js"></script>}我的控制器：[HttpGet]public ActionResult Add(){ FormDetailViewModel model = new FormDetailViewModel(); foreach(Form item in formRep.List().ProcessResult) { FormList.Add(new SelectListItem { Value = item.FormId.ToString(), Text = item.TeslimEden }); } foreach(Item item in itemRep.List().ProcessResult) { ?temList.Add(new SelectListItem { Value = item.ItemId.ToString(), Text = item.ItemDesc }); }
1 回答
呼啦一陣風
TA貢獻1802條經(jīng)驗 獲得超6個贊
控制器 ：
[HttpPost]
public JsonResult GetDataById(int id) {
//your logic
....
//response - return data which is required in your ajax success.
return Json(response, JsonRequestBehavior.AllowGet);
}
杰斯：
$('#Selection').on('change', function () {
var id = $('#Selection option:selected').text();
$.ajax({
url: '@Url.Action("GetDataById", "FormDetail")',
type: "POST",
data: { 'id': id },
success: function (result) {
$('#ajaxDisplay').html(result);
}
});
});
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