所以我應(yīng)該按照這種格式來查找文本文件的出現(xiàn)次數(shù)。但我的代碼可能是完全錯(cuò)誤的。text = open('text3.txt','r')d = dict()fname = input('Enter the file name:')l = input('Enter letter to be searched:')k = 0with open(fname, 'r') as f: for line in f: words = line.split() for i in words: for letter in i: if(letter == 1): k = k+1print('Occurences of the letter:')print(k)有人可以幫我嗎？
1 回答
MYYA
TA貢獻(xiàn)1868條經(jīng)驗(yàn) 獲得超4個(gè)贊
是的，您可以改為迭代字符：
fname = input('Enter the file name:')
char = input('Enter letter to be searched:')
i = 0
with open(fname, 'r') as f:
data = f.read()
for each in data:
if each == char:
i += 1
print(i)
添加回答
舉報(bào)
0/150
提交
取消