我的 Json 文件：{ "countries": [ "Australia", "France", "Belgium" ]}我有一個(gè)index_list = ['Germany', 'USA, 'Ireland, Australia, "France", Belgium, "Kenya", "Spain" 我想過(guò)濾掉 json 文件中的所有國(guó)家/地區(qū)。data_json= json.dumps(data["countries"])res = filter(lambda i: i not in data_json, index_list)print(res)這給了我<filter object at 0x0000022D05C0E6A0>錯(cuò)誤。
3 回答
月關(guān)寶盒
TA貢獻(xiàn)1772條經(jīng)驗(yàn) 獲得超5個(gè)贊
您可以將 JSON 數(shù)據(jù)轉(zhuǎn)換為 list() 并使用列表理解過(guò)濾其他數(shù)據(jù)。
import json
data_json = list(json.load(open('file.json'))['countries'])
index_list = ['Germany', 'USA', 'Ireland', 'Australia', "France", 'Belgium', "Kenya", "Spain"]
answer = [country for country in index_list if country not in data_json]
print(answer)
30秒到達(dá)戰(zhàn)場(chǎng)
TA貢獻(xiàn)1828條經(jīng)驗(yàn) 獲得超6個(gè)贊
您可以循環(huán)遍歷所有元素并檢查它們是否存在于 json 列表中，而不是過(guò)濾器
import json
data = {"countries": ["Australia", "France", "Belgium"]}
index_list = ["Germany", "USA", "Ireland", "Australia", "France", "Belgium", "Kenya", "Spain"]
data_json= json.dumps(data["countries"])
res = [item for item in index_list if item not in data_json]
print(res)
結(jié)果：['Germany', 'USA', 'Ireland', 'Kenya', 'Spain']
繁星點(diǎn)點(diǎn)滴滴
TA貢獻(xiàn)1803條經(jīng)驗(yàn) 獲得超3個(gè)贊
這是熊貓索引的一種方法。我們不需要循環(huán)（或列表理解），因?yàn)?Index 包含一個(gè)difference()方法。
import pandas as pd
data = {"countries": ["Australia", "France", "Belgium"]}
index_list = ["Germany", "USA", "Ireland", "Australia", "France",
"Belgium", "Kenya", "Spain"]
result = pd.Index(index_list).difference(data['countries']).to_list()
print(result)
['Germany', 'Ireland', 'Kenya', 'Spain', 'USA']
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