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用于查找格式錯(cuò)誤的引用字符串的正則表達(dá)式

用于查找格式錯(cuò)誤的引用字符串的正則表達(dá)式

Go
BIG陽(yáng) 2023-06-19 14:04:24
我正在嘗試為具有起始引號(hào)但沒(méi)有結(jié)束引號(hào)的子字符串構(gòu)建正則表達(dá)式。下面是一個(gè)示例字符串"The fish was 2 long. I said: Give me that fish!.The fish was 2" long. I said: Give me that fish!."The fish was 2 long. I said: Give me that fish!."The fish "was 2 long". I said: "Give me that fish!.所以表達(dá)式的有效輸出是String 1 - The fish was 2 long. I said: Give me that fish!String 2 -  long. I said: Give me that fish!.String 3 - No outputString 4 - Give me that fish!.任何想法如何構(gòu)建正則表達(dá)式。
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?
喵喵時(shí)光機(jī)

TA貢獻(xiàn)1846條經(jīng)驗(yàn) 獲得超7個(gè)贊

可以用正則表達(dá)式做所有事情.. 需要更多時(shí)間來(lái)完善解決方案。但是使用一些字符串函數(shù)會(huì)讓你輕松一些。


希望這可以幫助?。?/p>


package main


import (

"fmt"

"regexp"

"strings"

)


func main() {

str := `

    "The fish was 2 long. I said: Give me that fish!.

The fish was 2" long. I said: Give me that fish!.

"The fish was 2 long. I said: Give me that fish!."

""sdfsdf

`

splitStr := strings.Split(str, "\n")

re := regexp.MustCompile(`"{1}[A-Za-z0-9 .:!]+"{0}[A-Za-z0-9 .:!]+$`)

for _,v := range splitStr {

    if len(strings.Trim(v, " ")) >= 0{

    // some extra check

    if strings.Count(v, "\"") % 2 == 1 {

        fmt.Println( re.FindString(v))

    }


    } 

}

}


此處提供代碼示例: https: //play.golang.org/p/LYte6FRocv3


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反對(duì) 回復(fù) 2023-06-19
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