我正在嘗試為具有起始引號但沒有結(jié)束引號的子字符串構(gòu)建正則表達式。下面是一個示例字符串"The fish was 2 long. I said: Give me that fish!.The fish was 2" long. I said: Give me that fish!."The fish was 2 long. I said: Give me that fish!."The fish "was 2 long". I said: "Give me that fish!.所以表達式的有效輸出是String 1 - The fish was 2 long. I said: Give me that fish!String 2 - long. I said: Give me that fish!.String 3 - No outputString 4 - Give me that fish!.任何想法如何構(gòu)建正則表達式。
1 回答
喵喵時光機
TA貢獻1846條經(jīng)驗 獲得超7個贊
可以用正則表達式做所有事情.. 需要更多時間來完善解決方案。但是使用一些字符串函數(shù)會讓你輕松一些。
希望這可以幫助??！
package main
import (
"fmt"
"regexp"
"strings"
)
func main() {
str := `
"The fish was 2 long. I said: Give me that fish!.
The fish was 2" long. I said: Give me that fish!.
"The fish was 2 long. I said: Give me that fish!."
""sdfsdf
`
splitStr := strings.Split(str, "\n")
re := regexp.MustCompile(`"{1}[A-Za-z0-9 .:!]+"{0}[A-Za-z0-9 .:!]+$`)
for _,v := range splitStr {
if len(strings.Trim(v, " ")) >= 0{
// some extra check
if strings.Count(v, "\"") % 2 == 1 {
fmt.Println( re.FindString(v))
}
}
}
}
此處提供代碼示例： https: //play.golang.org/p/LYte6FRocv3
- 1 回答
- 0 關(guān)注
- 141 瀏覽
添加回答
舉報
0/150
提交
取消