我知道如何上傳單個(gè)文件，但現(xiàn)在我正嘗試在同一個(gè) Go 函數(shù)中上傳多個(gè)文件。這是我的代碼：func PhotoCreatePOST(w http.ResponseWriter, r *http.Request) { var err errorr.ParseMultipartForm(32 << 20) // 32MB is the default used by FormFilefhs := r.MultipartForm.File["files"]var fileNames []stringvar filename stringvar ext stringfor _, file := range fhs { //Iterate over multiple uploaded files if err != nil { log.Fatal(err) } else { dir, err := os.Getwd() if err != nil { log.Fatal(err) } ext = strings.ToLower(path.Ext(file.Filename)) filename = path.Join(random.RandString(10) + ext) destFolder := "/media/photos" if _, err := os.Stat(destFolder); os.IsNotExist(err) { os.Mkdir(destFolder, 0755) } //destination Path. The string which is Saving in DB savePath := destFolder + "/" + filename err = ioutil.WriteFile(savePath, file, 0777) //<--Here is the problem if err != nil { log.Println(err) io.WriteString(w, err.Error()) return } }}//Add file url to the slicefileNames = append(fileNames, filename)}但我收到此錯(cuò)誤：cannot use file (type *multipart.FileHeader) as type []byte in argument to ioutil.WriteFile我試過file像這樣讀入字節(jié)：b, err := ioutil.ReadFile(file) if err != nil { fmt.Print(err) }并保存b而不是file.但后來我得到另一個(gè)錯(cuò)誤can not read *multipart.Fileheader as string 我怎樣才能解決這個(gè)問題？
2 回答
冉冉說
TA貢獻(xiàn)1877條經(jīng)驗(yàn) 獲得超1個(gè)贊
這里是記錄的完整解決方案：
// PhotoCreatePOST saves multiple photo uploads
func PhotoCreatePOST(w http.ResponseWriter, r *http.Request) {
? ? err := r.ParseMultipartForm(100000)
? ? if err != nil {
? ? ? ? fmt.Println("error parsing multiplepart form", err)
? ? ? ? return
? ? }
? ? files := r.MultipartForm.File["files"]
? ? for i, _ := range files { //Iterate over multiple uploaded files
? ? ? ? file, err := files[i].Open()
? ? ? ? defer file.Close()
? ? ? ? if err != nil {
? ? ? ? ? ? fmt.Println("error opening file ", err)
? ? ? ? ? ? return
? ? ? ? }
? ? ? ? ext := path.Ext(files[i].Filename)
? ? ? ? //TODO: Verify extension is valid
? ? ? ? filename := GetRandomString(10) + ext
? ? ? ? //create destination file making sure the path is writeable.
? ? ? ? dst, err := os.Create("media/photos/" + filename)
? ? ? ? defer dst.Close()
? ? ? ? if err != nil {
? ? ? ? ? ? fmt.Println("error creating destination ", err)
? ? ? ? ? ? return
? ? ? ? }
? ? ? ? //copy the uploaded file to the destination file
? ? ? ? if _, err := io.Copy(dst, file); err != nil {
? ? ? ? ? ? fmt.Println("error copying file", err)
? ? ? ? ? ? return
? ? ? ? }
? ? ? ? fmt.Println("Image upload success: ", files[i].Filename)
? ? }
? ? fmt.Println("all are uploaded")
? ? PhotoCreateGET(w, r)
? ? return?
}
//Generate random filename (never trust user input!)
var letterRunes = []rune("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789")
// GetString returns a random string
func GetRandomString(n int) string {
? ? rand.Seed(time.Now().UnixNano())
? ? b := make([]rune, n)
? ? for i := range b {
? ? ? ? b[i] = letterRunes[rand.Intn(len(letterRunes))]
? ? }
? ? return string(b)
}
以及上傳表格：
<form method="post" action="/create/photo" enctype="multipart/form-data">
? ? ? ? <input type="file"? name="files"? multiple>
? ? ? ? <input type="hidden" name="token" value="{{.token}}">
? ? ? ? <button title="submit" type="submit" >Save </button>
</form>
瞧。希望它可以為其他人節(jié)省一些時(shí)間。
慕碼人8056858
TA貢獻(xiàn)1803條經(jīng)驗(yàn) 獲得超6個(gè)贊
這大致就是您的操作方式。
fileHeaders := r.MultipartForm.File["files"]
var fileNames []string
for _, fileHeader := range fileHeaders {
file, err := fileHeader.Open()
if err != nil {
return err
}
defer file.Close()
// Generate the destination filename randomly. Using even the passed
// extension is a security vulnerability unless you have a whitelist.
dest, err := ioutil.TempFile("/media/photos", "")
if err != nil {
return err
}
defer dest.Close()
if _, err := io.Copy(dest, file); err != nil {
return err
}
fileNames = append(fileNames, dest.Name())
}
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