我有兩個(gè)對(duì)象數(shù)組，我想基于它們創(chuàng)建第三個(gè)對(duì)象并添加一些新的鍵/值?；A(chǔ)數(shù)據(jù)const oldArray = [{id: 1, name: 'Test', age: 25, skill: 120},?{id: 2, name: 'Test25', age: 10, skill: 120}];修改后的數(shù)據(jù)const newArray = [{id: 1, name: 'Test2', age: 50, skill: 200},{id: 2, name: 'Test25', age: 25, skill: 120}];我想收到類(lèi)似的東西：const expectedResultArray = [? {id: 1, oldName: 'Test', newName: 'Test2', oldAge: 25, newAge: 50, ageDifference: 25, oldSkill: 120, newSkill: 200, skillDifference: 80 },? {id: 2, oldName: 'Test25', newName:'Test25', oldAge: 10, newAge: 25, ageDifference: 15, oldSkill:120, newSkill: 120, skillDefference: 0}]如您所見(jiàn)，預(yù)期數(shù)組是基于兩個(gè)數(shù)組的舊計(jì)算和全新計(jì)算的組合。我怎樣才能做到這一點(diǎn)？我試過(guò)reduce()但是我被困在嘗試中：var createNewArray = (...objects) =>?? Object.values(objects.reduce((a, e) => {? ? a[e.id] = a[e.id] || {id: e.id};? // struggling to proceed here?? ? return a;? }, {}));console.log(createNewArr(...oldArray, ...newArray));