給定以下類，完成 Student 類的代碼，以便在我們運(yùn)行 Q01 類時(shí)打印以下輸出。提示：學(xué)生類是 Person 的子類這是輸出：部門：CSE，ID：20101001，姓名：Mark Wahlberg部門：BBA，ID：20101002，姓名：Zeeko Zaki部門：CSE，編號(hào)：20101002，姓名：Zeeko Zakipublic abstract class Person { private String name; private Person() { } Person(String name) { this.name = name; } protected String getName() { return name; } protected void setName(String name) { this.name = name; }}public class Q01 { public static void main(String[] args) { Student s1 = new Student("CSE", 20101001, "Mark Wahlberg"); Student s2 = new Student("BBA", 20101002, "Zeeko Zaki"); s1.printDetail(); s2.printDetail(); s2.setDepartment("CSE"); s2.printDetail(); }}我在班級(jí)下面創(chuàng)建了一個(gè)新班級(jí)public class Student extends Person{ public String department=""; public int id; public String name; public String Public(String name){ return name; } public Student(String department,int id,String name){ this.department=department; this.id=id; this.name=name; } public void setDepartment(String department){ this.department=department; } public String getDepartment(){ return department; } public void printDetail(){ System.out.println("Department: "+this.department+", ID: "+this.id+", Name: "+name); }} 我無法編譯這段代碼。如何解決這個(gè)問題呢？我的錯(cuò)誤在哪里？
1 回答
慕姐4208626
TA貢獻(xiàn)1852條經(jīng)驗(yàn) 獲得超7個(gè)贊
Student 的構(gòu)造函數(shù)需要先調(diào)用父類的構(gòu)造函數(shù)。
為此，您需要調(diào)用“super”并傳遞正確的參數(shù)，在這種情況下，父類（Person）有 2 個(gè)構(gòu)造函數(shù)，默認(rèn)構(gòu)造函數(shù)是私有的，并且只能在 Person 類中訪問，因此您必須使用第二個(gè)構(gòu)造函數(shù)子類 Student，它采用字符串名稱。艾
public Student(String department,int id,String name){
super(name);
this.department=department;
this.id=id;
this.name=name;
}
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