我正在學(xué)習(xí)如何使用 concurrent withexecutor.map()和executor.submit()。我有一個(gè)包含 20 個(gè) url 的列表，想同時(shí)發(fā)送 20 個(gè)請(qǐng)求，問(wèn)題是.submit()從一開(kāi)始就以與給定列表不同的順序返回結(jié)果。我讀過(guò)它map()可以滿足我的需要，但我不知道如何用它編寫代碼。下面的代碼對(duì)我來(lái)說(shuō)很完美。問(wèn)題：是否有任何代碼塊map()等同于下面的代碼，或者任何排序方法可以submit()按給定列表的順序?qū)Y(jié)果列表進(jìn)行排序？import concurrent.futuresimport urllib.requestURLS = ['http://www.foxnews.com/',        'http://www.cnn.com/',        'http://europe.wsj.com/',        'http://www.bbc.co.uk/',        'http://some-made-up-domain.com/']# Retrieve a single page and report the url and contentsdef load_url(url, timeout):    with urllib.request.urlopen(url, timeout=timeout) as conn:        return conn.read()# We can use a with statement to ensure threads are cleaned up promptlywith concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:    # Start the load operations and mark each future with its URL    future_to_url = {executor.submit(load_url, url, 60): url for url in URLS}    for future in concurrent.futures.as_completed(future_to_url):        url = future_to_url[future]        try:            data = future.result()        except Exception as exc:            print('%r generated an exception: %s' % (url, exc))        else:            print('%r page is %d bytes' % (url, len(data)))