我有一個如下所示的枚舉public enum MyBeanType { Type1, Type2 ... Type100;}我想為每個枚舉值創(chuàng)建一個 Bean。public Class MyBean { private MyBeanType type; public MyBean(MyBeanType type) { this.type = type; }}我知道我可以像這樣在我的配置中列出每一個：@Configurationpublic class MyBeanConfig() { @Bean public MyBean myBeanType1() { return new MyBean(MyBeanType.Type1); @Bean public MyBean myBeanType2() { return new MyBean(MyBeanType.Type2); ... @Bean public MyBean myBeanType100() { return new MyBean(MyBeanType.Type100); }但是有沒有辦法更動態(tài)地做到這一點(diǎn)？我通常將所有這些連接為一個List，但在某些情況下我也想按myBeanType2名稱連接。
2 回答
蝴蝶不菲
TA貢獻(xiàn)1810條經(jīng)驗(yàn) 獲得超4個贊
編寫自定義BeanFactoryPostProcessor來玩轉(zhuǎn) bean 定義。
@Bean
public BeanFactoryPostProcessor getBeanFactoryPostProcessor() {
? return beanFactory -> {
? ? for (int i = 0; i < MyBeanType.values().length; i++) {
? ? ? beanFactory.registerSingleton(MyBeanType.class.getSimpleName() + i,?
? ? ? ? new MyBean(MyBeanType.values()[i]));
? ? }
? };
}
慕妹3146593
TA貢獻(xiàn)1820條經(jīng)驗(yàn) 獲得超9個贊
您可以簡單地以編程方式注冊 bean。應(yīng)該這樣做。
@Configuration
public class MyBeanConfig() implements ApplicationContextAware {
@Override
public void setApplicationContext(final ApplicationContext ctx) {
final ConfigurableListableBeanFactory beanFactory = ((ConfigurableApplicationContext) ctx).getBeanFactory();
for(final MyBeanType beanType: MyBeanType.values()) {
beanFactory.registerSingleton(MyBean.class.getCanonicalName() + "_" + beanType, new MyBean(beanType));
}
}
}
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