我試圖從存儲在表中的 url 獲取圖像，但是當我嘗試獲取圖像時，ImageView 不包含任何內容，它只是空白。在我下面的代碼中，我使用 Picasso 來獲取圖片：public class Imageoffam extends AppCompatActivity {private boolean success = false; // booleanprivate ConnectionClass connectionClass;public TextView tmtmt;public ImageView dede;@Overrideprotected void onCreate(Bundle savedInstanceState) {    super.onCreate(savedInstanceState);    setContentView(R.layout.activity_imageoffam);    getSupportActionBar().hide();    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,            WindowManager.LayoutParams.FLAG_FULLSCREEN);    tmtmt = (TextView) findViewById(R.id.tomato) ;    dede = (ImageView) findViewById(R.id.dededede);    connectionClass = new ConnectionClass();    SyncData orderData = new SyncData();    orderData.execute("");}private class SyncData extends AsyncTask<String, String, String> {    String msg = "Success";    ProgressDialog progress;    @Override    protected void onPreExecute() {        progress = ProgressDialog.show(Imageoffam.this, "Synchronising",                "Please Wait...", true);    }    @Override    protected String doInBackground(String... strings) {        try {            Connection conn = connectionClass.CONN();            if (conn == null) {                msg = "Please Check Your Connection";                success = false;            } else {                String dta = getIntent().getStringExtra("blala");                String query = "SELECT Images.Fimage,family.FName,family.FInfo,family.CID FROM Images INNER JOIN family ON family.FID = Images.FID WHERE family.FInfo = (N'" +dta+ "')";                Statement stmt = conn.createStatement();                ResultSet rs = stmt.executeQuery(query);盡管它沒有在 ImageView 中顯示圖像，但它沒有給出任何錯誤消息。有人可以告訴我我做錯了什么嗎？任何幫助，將不勝感激。