我正在使用DOMDocument. 那很好用。我需要解析我的 XML，找到特定的值，然后只再次顯示某些節(jié)點(diǎn)。XML 看起來像這樣......<rss version="2.0"> <channel> <title>Title</title> <link></link> <item> <title>Title #1</title> <description>Here I want to filter</description> </item> <item> <title>Title #2</title> <description>Should not be displayed</description> </item></channel>我想在描述標(biāo)簽內(nèi)搜索，如果找到關(guān)鍵字我想顯示item. 如果找不到，我想刪除 parent item。到目前為止，這就是我嘗試過的...<?phpheader('Content-Type: text/xml');// Load our XML document$rss = new DOMDocument();$rss->load('https://myurl');$description = $rss->getElementsByTagName('description');foreach ($description as $node) { $s = $node->nodeValue; if (strpos($s, 'filter') !== false) { //found the keyword, nothing to delete } else { //didnt find it, now delete item $node->parentNode->parentNode->removeChild($node->parentNode); }}echo $description->saveXml();我正在嘗試獲取所有描述節(jié)點(diǎn)，檢查它們是否包含字符串，如果不包含，則刪除父節(jié)點(diǎn)。搜索字符串有效，但刪除節(jié)點(diǎn)無效。如果我回顯我的 XML，則沒有任何改變。
1 回答
慕桂英3389331
TA貢獻(xiàn)2036條經(jīng)驗(yàn) 獲得超8個贊
getElementsByTagName()將返回“實(shí)時”結(jié)果。如果您修改文檔，它將發(fā)生變化。您可以用來iterator_to_array()制作穩(wěn)定的副本。
另一種選擇是使用 Xpath 表達(dá)式來獲取特定節(jié)點(diǎn)。
$document = new DOMDocument();
$document->loadXML($xmlString);
$xpath = new DOMXpath($document);
// fetch items that contain "filter" in their description
$items = $xpath->evaluate('/rss/channel/item[contains(description, "filter")]');
foreach ($items as $item) {
// dump the title child element text content
var_dump($xpath->evaluate('string(title)', $item));
}
// fetch items that do not contain "filter" in their description
$items = $xpath->evaluate('/rss/channel/item[not(contains(description, "filter"))]');
foreach ($items as $item) {
// remove item element
$item->parentNode->removeChild($item);
}
echo $document->saveXML();
輸出：
string(8) "Title #1"
<?xml version="1.0"?>
<rss version="2.0">
<channel>
<title>Title</title>
<link/>
<item>
<title>Title #1</title>
<description>Here I want to filter</description>
</item>
</channel>
</rss>
- 1 回答
- 0 關(guān)注
- 209 瀏覽
添加回答
舉報(bào)
0/150
提交
取消