[ { "pid": "1", "pname": "Burger", "price": "20", "qnty": "1", "pimg": "1.jpg" }, { "pid": "2", "pname": "Cheese burger", "price": "30", "qnty": "1", "pimg": "2.jpg" }]我有一個像上面這樣的數(shù)組。如何檢查數(shù)組是否有特定的“pid”。例如，如果數(shù)組有“pid”1，則顯示view button，否則顯示add to cart button
4 回答
千萬里不及你
TA貢獻1784條經(jīng)驗 獲得超9個贊
foreach ($array as $item){
if($item->pid == 1) {
//do some work...
}
}
神不在的星期二
TA貢獻1963條經(jīng)驗 獲得超6個贊
$array = [
{
"pid": "1",
"pname": "Burger",
"price": "20",
"qnty": "1",
"pimg": "1.jpg"
},
{
"pid": "2",
"pname": "Cheese burger",
"price": "30",
"qnty": "1",
"pimg": "2.jpg"
}
]
你可以使用isset功能。
$key = 1;
$count =0 ;
foreach($array as $a) {
if(isset(array_search($key,$a))){
//your logic to execute if the $key is there in the array
$count ++;
}
}
if($count==0){
//add to cart logic
}
千巷貓影
TA貢獻1829條經(jīng)驗 獲得超7個贊
您需要使用循環(huán)迭代數(shù)組，然后根據(jù)數(shù)組的任何索引檢查值
foreach ($items as $item){
if($item->pid == 1) {
// do whatever you want to do
}
}
慕仙森
TA貢獻1827條經(jīng)驗 獲得超8個贊
您可以利用isset()和!empty()
foreach($lists as $list) {
if(isset($list['pid']) && (!empty($list['pid']))) { // this will check if a key exists. If yes, then check for it's value. If value is there, then true
// pid exists and has a value
} else {
}
}
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