我想根據(jù)數(shù)組對數(shù)組數(shù)組進行排序，然后按數(shù)組中項目的長度進行排序。采用以下主排序數(shù)組：const key = [  "meraki",  "gsuite",  "active directory",  "sophos",  "manageengine"]我想采用類似于以下內(nèi)容的數(shù)組：const raw = [  ["manageengine"],  ["sophos"],  ["active directory"],  ["gsuite"],  ["meraki"],  ["sophos", "manageengine"],  ["active directory", "sophos"],  ["active directory", "manageengine"],  ["gsuite", "active directory"],  ["gsuite", "sophos"],  ["gsuite", "manageengine"],  ["meraki", "gsuite"],  ["meraki", "active directory"],  ["meraki", "sophos"],  ["meraki", "manageengine"],  ["active directory", "sophos", "manageengine"],  ["gsuite", "active directory", "sophos"],  ["gsuite", "active directory", "manageengine"],  ["gsuite", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory"],  ["meraki", "gsuite", "sophos"],  ["meraki", "active directory", "sophos"],  ["meraki", "gsuite", "manageengine"],  ["meraki", "active directory", "manageengine"],  ["meraki", "sophos", "manageengine"],  ["gsuite", "active directory", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory", "sophos"],  ["meraki", "gsuite", "active directory", "manageengine"],  ["meraki", "gsuite", "sophos", "manageengine"],  ["meraki", "active directory", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory", "sophos", "manageengine"]];在上面的示例中，我希望raw根據(jù)key數(shù)組中的每個項目對數(shù)組進行排序。我的第一次嘗試是做類似的事情：const result = [];for (const name of result) {  const sorted = keys.filter((s) => s[0] === name);  result.push(...sorted);}result.sort((a, b) => a.length - b.length);但是，這只考慮了數(shù)組中的第一項，而不考慮其余項的排序。