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比較 2 個(gè)文本文件并找出列表中的差異并找出哪些列表值不匹配

Java

白衣染霜花 2023-05-24 16:11:58

我正在使用 Scanner 讀取 2 個(gè)文本文件（可能包含重復(fù)項(xiàng)）并將它們寫入 arraylist。我正在比較兩個(gè) arraylist 以找出差異。當(dāng)我打印出來時(shí)，我可以看到有什么區(qū)別，但我不知道哪個(gè)記錄來自哪個(gè)文件（文本文件名）text1.txt 中的內(nèi)容TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,text2.txt 中的內(nèi)容TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,代碼：Scanner prodScanner = new Scanner(prodFile); while (prodScanner.hasNextLine()) { String currentRecord = prodScanner.nextLine().trim(); if (currentRecord.length() > 0) { prodRecordsFromStatement.add(currentRecord); } }Scanner nonProdScanner = new Scanner(nonProdFile);while (nonProdScanner.hasNextLine()) { String currentRecord = nonProdScanner.nextLine().trim(); if (currentRecord.length() > 0) { nonProdRecordsFromStatement.add(currentRecord); } }Collection<String> result = new ArrayList<>(CollectionUtils.disjunction(prodRecordsFromStatement, nonProdRecordsFromStatement)); List<String> resultList = new ArrayList<>(result); Collections.sort(resultList);

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2 回答

婷婷同學(xué)_

TA貢獻(xiàn)1844條經(jīng)驗(yàn) 獲得超8個(gè)贊

遍歷resultList檢查以查看當(dāng)前項(xiàng)目是否也在prodRecordsFromStatement.

如果是，則來自文件 1，否則來自文件 2。

反對(duì) 回復(fù) 2023-05-24

HUH函數(shù)

TA貢獻(xiàn)1836條經(jīng)驗(yàn) 獲得超4個(gè)贊

您的解決方案需要具備怎樣的性能？如果性能不是非常關(guān)鍵，并且您的列表不長(zhǎng)，那么您可以改用 usingsubtract而不是 disjunction。

例如

Collection<String> resultProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));
Collection<String> resultNonProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));

resultProdRecords將包含 prodRecordsFromStatement 中不在 nonProdRecordFromStatement 中的所有行。

resultNonProdRecords將包含 nonProdRecordFromStatement 中不在 prodRecordsFromStatement 中的所有行。

反對(duì) 回復(fù) 2023-05-24