登錄后，我自動連接到主頁。按下按鈕時，我想在 spring boot 中訪問控制器上的“findAllUsers”方法，并以表格格式顯示注冊用戶。我為此使用了ajax get call。但是我得到了我在下面的照片中提到的控制臺錯誤。我需要改變什么？我應(yīng)該怎么辦？USER.java@Data@Entity@Table(name = "user")public class User {    @Id    @GeneratedValue(strategy = GenerationType.AUTO)    @Column(name = "user_id")    private int id;    @Column(name = "email")    @Email(message = "*Please enter a valid Email")    @NotEmpty(message = "*Please provide an email")    private String email;    @Column(name = "password")    @Length(min = 5, message = "*Your password must have at least 5 characters")    @NotEmpty(message = "*Please enter your password")    private String password;    @Column(name = "name")    @NotEmpty(message = "*Please enter your name")    private String name;    @Column(name = "last_name")    @NotEmpty(message = "*Please enter your last name")    private String lastName;    @Column(name = "active")    private int active;    @ManyToMany(cascade = CascadeType.ALL)    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "role_id"))    private Set<Role> roles;    //G&S    public int getId() {        return id;    }    public void setId(int id) {        this.id = id;    }    public String getEmail() {        return email;    }    public void setEmail(String email) {        this.email = email;    }    public String getPassword() {        return password;    }    public void setPassword(String password) {        this.password = password;    }    public String getName() {        return name;    }    public void setName(String name) {        this.name = name;    }    public String getLastName() {        return lastName;    }    public void setLastName(String lastName) {        this.lastName = lastName;    }    public int getActive() {        return active;    }