所以說到正則表達(dá)式我javascript，我只知道1%左右。我正在嘗試編寫一些代碼來檢測數(shù)學(xué)表達(dá)式（例如 2 + 3）。前段時間我在另一個問題上發(fā)現(xiàn)了這個：/(?:(?:^|[-+_*/])(?:\s*-?\d+(\.\d+)?(?:[eE][+-]?\d+)?\s*))+$/I這似乎工作正常，但我只希望它在前面有特定關(guān)鍵字時工作。所以現(xiàn)在我有這樣的東西：var re = /(?:(?:^|[-+_*/])(?:\s*-?\d+(\.\d+)?(?:[eE][+-]?\d+)?\s*))+$/i;var str = "2 + 2";console.log(str.match(re));但我想要這個：var keyword = "Some keyword ";var str = `${keyword}2 + 2`;//Regular expressio that should only work if "Some keyword" and math expression are therevar re = //the expression//should match the stringconsole.log(str.match(re));//But if the keiword is not therevar keyword = "";var str = `${keyword}2 + 2`;//Regular expressio that should only work if "Some keyword" and math expression are therevar re = //the expression//should NOT match the stringconsole.log(str.match(re));我試過這個，但它并沒有真正達(dá)到我的預(yù)期：var one = /Some keyword /i;var two = /(?:(?:^|[-+_*/])(?:\s*-?\d+(\.\d+)?(?:[eE][+-]?\d+)?\s*))+$/i;var one_or_two = new RegExp("(" + one.source + ")?(" + two.source + ")")var str = "Some keyword 2 + 1";alert(str.match(one_or_two))我需要在正則表達(dá)式中使用所有這些，因為我不能使用 str.match(re)有沒有辦法做到這一點(diǎn)？無論如何提前感謝。