我有一個(gè)我無(wú)法解決的問(wèn)題。我正在使用https://github.com/kmanley/golang-tuple創(chuàng)建元組。我有一份會(huì)議記錄清單：minutes := int{0, 30} // Minutes are 0 and 30以及四個(gè)參數(shù)：start, startBreak, stop, stopBreak：start := tuple.NewTupleFromItems(9, 30) // It represents "9:30"startBreak := tuple.NewTupleFromItems(12, 0) // It represents "12:00"stop := tuple.NewTupleFromItems(21, 0) // It represents "21:00"stopBreak := tuple.NewTupleFromItems(14, 30) // It represents "14:30"(hour, minutes)我想使用切片中的所有分鐘來(lái)獲得一片元組minutes，并且它們不能包含在范圍內(nèi)startBreak-stopBreak（它可以等于startBreakor stopBreak，因此范圍將變?yōu)?2:30, 13:00, 13:30, 14:00）和stop-start（它可以等于startand stop，因此范圍會(huì)變成21:30, 22:00, 22:30, ..., 8:30, 9:00）。例如，使用這四個(gè)參數(shù)，最終結(jié)果將是：9:30, 10:00, 10:30, 11:00, 11:30, 12:00, 14:30, 15:00, 15:30, 16:00, 16:30, 17:00, 17:30, 18:00, 18:30, 19:00, 19:30, 20:00, 20:30, 21:00
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當(dāng)年話下
TA貢獻(xiàn)1890條經(jīng)驗(yàn) 獲得超9個(gè)贊
這是演示這一點(diǎn)的最小代碼，我沒(méi)有進(jìn)行任何數(shù)據(jù)驗(yàn)證。
func periods(minutes, start, startBreak, stopBreak, stop *tuple.Tuple) (out []tuple.Tuple) {
// next() moves current to the next minute interval
i := 0
curr := tuple.NewTupleFromItems(start.Get(0), minutes.Get(0))
next := func() {
i = (i + 1) % minutes.Len()
curr.Set(1, minutes.Get(i))
if i == 0 {
curr.Set(0, curr.Get(0).(int)+1)
}
}
for ; curr.Le(stop); next() {
if (curr.Ge(start) && curr.Le(startBreak)) || (curr.Ge(stopBreak) && curr.Le(stop)) {
out = append(out, *curr.Copy())
}
}
return out
}
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