我有一組具有不同 userIds 的用戶，我正在嘗試使用 foreach 循環(huán)來循環(huán)這些數(shù)組。在該循環(huán)中，我正在調(diào)用一個函數(shù)，通過將每個用戶的 userid 傳遞給一個函數(shù)來獲取每個用戶的值。但它只傳遞一個數(shù)組索引。我的代碼public function getDailyReportTest($orgId, $date){    $query = $this->db->query("SELECT *  FROM `organization_users` WHERE orgId='7'");       $timestamp = strtotime($date);       $day = date('l', $timestamp);   $data = array();$i = 0;foreach ($query->result_array() as $row) {  $data[$i]['date']    = $date;  $data[$i]['day']     = $day;  $data[$i]['user_id'] = $row['orgUserId'];  $data[$i]['user_name'] = $row['orgUserName'];  $data[$i]['workingHours'] = self::getUserWorkingHours($data[$i]['user_id'],$date);  $delayTime=self::getUserDelayTime($row['orgUserId'],$date);  $shortTime=self::getUserShortTime($row['orgUserId'],$date);  $overTime=self::getUserOverTime($row['orgUserId'],$date);     $data[$i]['delayTime']   =$delayTime;     $data[$i]['shortTime']   =$shortTime;     $data[$i]['overTime']    =$overTime;   $data[$i]['shift1_start'] = self::getUserShiftStartTime($row['orgUserId'], $date);    $i=$i+1;}//return $data;print_r($data);die();}public function getUserShiftStartTime($userId, $date){    $query = $this->db->query("SELECT * FROM `office_employee_assigned_shifts` WHERE employeeId='$userId' &&shiftdate='$date'");    $entry = $query->num_rows();    $data = $query->result_array();    if($entry==0)    {        return NULL;    }它只傳遞 $data[1]['user_id']。我想將 $data[0]['user_id'], $data[1]['user_id'], $data[2]['user_id'] 傳遞給名為 getUserShiftStartTime($userId, $date) 的函數(shù)有幫助嗎？我在這里先向您的幫助表示感謝