我已經看到了所有與我相關的問題，但仍然沒有找到解決我的“簡單”問題的方法。我有一個 3 維數組，我只想顯示結果。但是當我回應時，. "<td>".$person ['job']."</td>"我收到了錯誤。任何建議thnx$people= array(array( "name" => "Jennifer Kimbers", "age"=>"45", "email" => "abc@gmail.com", "city" => "Seattle", "state" => "Washington"), array( "job"=>"web developer" ),array( "name" => "Rodney Hutchers", "age"=>"55", "email" => "def@gmail.com", "city" => "Los Angeles", "state" => "California"), array( "job"=>"data developer" );echo "<table>" ."<th>FullName</th>" ."<th>Age</th>" ."<th>Email</th>" ."<th>City</th>" ."<th>State</th>" ."<th>Job</th>"; foreach ($people as $person) { echo "<tr>" . "<td>" . $person ['name'] . "</td>" . "<td>" . $person ['age'] . "</td>" . "<td>" . $person ['email'] . "</td>" . "<td>" . $person ['city'] . "</td>" . "<td>" . $person ['state'] . "</td>" . "<td>" . $person ['job'] . "</td>" . "</tr>";}echo "</table>";
1 回答
翻過高山走不出你
TA貢獻1875條經驗 獲得超3個贊
您的數組結構略有偏差，在
array(
"name" => "Jennifer Kimbers",
"age"=>"45",
"email" => "abc@gmail.com",
"city" => "Seattle",
"state" => "Washington"), // Close bracket here
array(
"job"=>"web developer"
),
這個縮進正確的是
array(
"name" => "Jennifer Kimbers",
"age"=>"45",
"email" => "abc@gmail.com",
"city" => "Seattle",
"state" => "Washington"),
array(
"job"=>"web developer"),
所以你的循環(huán)試圖將它用作兩個單獨的數據位，而第二個不包含你期望的很多字段。
您需要確保在正確的位置關閉數組元素/將作業(yè)添加到與其余數據相同的元素中......
array(
"name" => "Jennifer Kimbers",
"age"=>"45",
"email" => "abc@gmail.com",
"city" => "Seattle",
"state" => "Washington", // Move ) after the job
"job" => "web developer"
),
如果您需要額外級別的數組，那么您可以將其列為工作列表......
array(
"name" => "Jennifer Kimbers",
"age"=>"45",
"email" => "abc@gmail.com",
"city" => "Seattle",
"state" => "Washington",
"jobs" => array( "title" => "web developer")
),
顯示它們
foreach ($people as $person) {
echo "<tr>"
. "<td>" . $person ['name'] . "</td>"
. "<td>" . $person ['age'] . "</td>"
. "<td>" . $person ['email'] . "</td>"
. "<td>" . $person ['city'] . "</td>"
. "<td>" . $person ['state'] . "</td>"
. "<td>";
foreach ( $person['jobs'] as $job ) {
echo $job . "/";
}
echo "</td>"
. "</tr>";
}
雖然這樣你最終會/在職位名稱后面有一個尾隨，但它顯示了原則。您可以代替內部foreach()循環(huán)使用...
echo implode("/", $person['jobs']);
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