我設(shè)置了 10 個(gè)“標(biāo)簽”，每個(gè)都有一個(gè) ID（格式：00:00:00:xx:xx:xx）和 translatedID（格式：TXT）。我得到字符串列表違反標(biāo)簽，我想將其從 translatedID 轉(zhuǎn)換為 ID。我有一個(gè)定義值的映射：Map(10) { '00:00:00:02:28:47' => 'T7T', '00:00:00:02:89:70' => 'T3T', '00:00:00:02:89:51' => 'T4T', '00:00:00:02:27:bd' => 'T5T', '00:00:00:02:89:31' => 'T6T', '00:00:00:02:89:a0' => 'T1T', '00:00:00:02:89:af' => 'T2T', '00:00:00:02:89:4d' => 'T9T', '00:00:00:02:89:28' => 'T10T', '00:00:00:02:89:a1' => 'T8T'}例子：input = 'T4T____T5T____T2T____T10T____T6T____'(desired) output = '00:00:00:02:89:51, 00:00:00:02:27:bd, 00:00:00:02:89:af, 00:00:00:02:89:28, 00:00:00:02:89:31'我的第一個(gè)想法是遍歷映射中的每個(gè)值，查看它是否存在于輸入中，如果存在，則將相應(yīng)的 ID 添加到輸出中。但由于不必要的額外循環(huán)，這不是最優(yōu)的。有什么建議么？此外，我的代碼使用全局變量來定義地圖變量。我知道這是不受歡迎的，我有更好的方法嗎？我的代碼格式如下：let dict = new Map()function customQueryString() { return new Promise((resolve, reject) => { client.query(query, (err, res) => { res.rows.forEach(psqltag => { dict.set(psqltag.m_violator_tag, psqltag.m_translatedid) }); resolve(queryStringAddition) // defined elsewhere doesnt matter for this problem }) })}function loopingQueryFunction(loopQuery) { client.query(loopQuery, (err, res) => { res.rows.forEach(tag => { input = tag.violating_tags // where the input string is found output = ??? // where the translation needs to happen } }}async function asyncCall() { let qStringAddition = await customQueryString(); loopQuery = loopQuery + qStringAddition for (let i = 0; i< 100; i++) { console.log("loop " + i) await delay(1000) loopingQueryFunction(loopQuery) }}
在javascript中使用map替換具有不同名稱的ID字符串的最佳方法
精慕HU
2023-04-27 10:43:42
