我在 Android 應(yīng)用程序中有一個(gè)選項(xiàng)可以設(shè)置兩個(gè)通知?；旧?，當(dāng)用戶單擊按鈕時(shí)，將顯示一個(gè)時(shí)間選擇器，在第一次選擇器完成后，將彈出第二個(gè)時(shí)間選擇器供用戶第二次插入。兩個(gè)時(shí)間選擇器都在不同的方法中，在第一種方法結(jié)束時(shí)顯示吐司，與第二種方法相同。問題是當(dāng)?shù)谝淮芜x擇器完成時(shí)，兩條吐司消息立即觸發(fā)，然后當(dāng)用戶第二次完成選擇器時(shí)，第二條吐司消息再次觸發(fā)。我已經(jīng)包含了下面的代碼。 /** * Method which sets the first daily notification */private void startTwiceDailyNotification(Calendar c) { DialogFragment timePicker = new TimePickerFragment(); AlarmManager alarmManager = (AlarmManager) getSystemService(Context.ALARM_SERVICE); Intent intent = new Intent(this, AlertReceiver.class); PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 1, intent, 0); alarmManager.setExact(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), pendingIntent); alarmManager.setRepeating(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pendingIntent); Toast.makeText(this, "First Notification Set.", Toast.LENGTH_SHORT).show(); timePicker.show(getSupportFragmentManager(), "time picker4"); hasSelected = 2;}/** * Method which sets the second daily notification */private void startTwiceDailyNotification2(Calendar c) { AlarmManager alarmManager = (AlarmManager) getSystemService(Context.ALARM_SERVICE); Intent intent = new Intent(this, AlertReceiver.class); PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 2, intent, 0); alarmManager.setExact(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), pendingIntent); alarmManager.setRepeating(AlarmManager.RTC_WAKEUP, c.getTimeInMillis(), AlarmManager.INTERVAL_DAY, pendingIntent); Toast.makeText(this, "Second Notification Set.", Toast.LENGTH_SHORT).show();}
3 回答
白板的微信
TA貢獻(xiàn)1883條經(jīng)驗(yàn) 獲得超3個(gè)贊
就像您可以閱讀此答案一樣。:
當(dāng)您編寫多個(gè) if 語句時(shí)，可能會(huì)有多個(gè) if 語句被評(píng)估為 true，因?yàn)檫@些語句彼此獨(dú)立。
當(dāng)您編寫單個(gè) if else-if else-if ... else 語句時(shí)，只能將一個(gè)條件評(píng)估為 true（一旦找到評(píng)估為 true 的第一個(gè)條件，將跳過下一個(gè) else-if 條件）。
因此，在您的示例中，在 method 之后startTwiceDailyNotification，變量hasSelected設(shè)置為 2。因此第二個(gè)“if 語句”被評(píng)估為 true，這就是startTwiceDailyNotification2調(diào)用 method 的原因。
要修復(fù)它，您應(yīng)該使用“一個(gè) if else-if else-if ... else 語句”，如下所示：
@Override
public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
calendar.set(Calendar.HOUR_OF_DAY, hourOfDay);
calendar.set(Calendar.MINUTE, minute);
calendar.set(Calendar.SECOND, 0);
if (hasSelected == 1) {
startTwiceDailyNotification(calendar);
}
else if (hasSelected == 2) {
startTwiceDailyNotification2(calendar);
}
}
DIEA
TA貢獻(xiàn)1820條經(jīng)驗(yàn) 獲得超3個(gè)贊
hasSelected = 2;被標(biāo)記這就是它出現(xiàn)的原因。hasselected =1單擊按鈕時(shí)首先設(shè)置。
試試這個(gè)方法：
@Override
public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
calendar.set(Calendar.HOUR_OF_DAY, hourOfDay);
calendar.set(Calendar.MINUTE, minute);
calendar.set(Calendar.SECOND, 0);
if (hasSelected == 1) {
startTwiceDailyNotification(calendar);
} else
if (hasSelected == 2) {
startTwiceDailyNotification2(calendar);
}
}
揚(yáng)帆大魚
TA貢獻(xiàn)1799條經(jīng)驗(yàn) 獲得超9個(gè)贊
塊內(nèi)發(fā)現(xiàn)邏輯錯(cuò)誤
@Override
public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
calendar.set(Calendar.HOUR_OF_DAY, hourOfDay);
calendar.set(Calendar.MINUTE, minute);
calendar.set(Calendar.SECOND, 0);
if (hasSelected == 1) {
//At this point hasSelected is 1
startTwiceDailyNotification(calendar);
//At this point hasSelected is 2
}
//No **else** statement so the next if statement is also checked
//Use an else here to prevent this block from executing when previous is true
if (hasSelected == 2) {
//Next code executed also
startTwiceDailyNotification2(calendar);
}
}
添加回答
舉報(bào)
0/150
提交
取消