有沒(méi)有更pythonic的方式來(lái)做到這一點(diǎn)？輸入：list1 =  [['a',1],['b',2],['c',3],['d',4]]list2 =  [['e',5],['f',6],['g',7],['h',8]]期望的輸出：out = [['a',1],['e',5],['b',2],['f',6],['c',3],['g',7],['d',4] ,['h',8]]我已經(jīng)做好了：def mergePreserveOrder(*argv):          for arg in argv:          for arg2 in argv:             if(len(arg) != len(arg2)) :                print("arrays size do not match" + str(arg) +  str(arg2))                                return     output = []        for index in range (len(argv[0])):            for arg in argv:            output.append(arg[index])        return  outputmergePreserveOrder (list1 ,list2  )