如果滿足條件，我希望能夠?qū)ΧS數(shù)組中的特定元素執(zhí)行操作。在下面的示例中，代碼使任何值 < 0.5 = 0。有誰知道這樣做的簡(jiǎn)單方法？下面是我的代碼，但我確信有更簡(jiǎn)單的方法。import numpy as npx = 5y = 5x3 = np.random.rand(x,y)def choice(arr): row = -1 column = -1 for i in arr: row += 1 for j in i: column += 1 if j >= 0.5: arr[row,column] = j else: arr[row,column] = 0 if column == y - 1: column = -1 return arry3 = choice(x3.copy())
2 回答
湖上湖
TA貢獻(xiàn)2003條經(jīng)驗(yàn) 獲得超2個(gè)贊
要將所有 < 0.5 的索引歸零，
>>> x3 = np.random.rand(5, 5)
>>> x3
array([[0.50866152, 0.56821455, 0.88531855, 0.36596337, 0.08705278],
[0.96215686, 0.19553668, 0.15948972, 0.20486815, 0.74759719],
[0.36269356, 0.54718917, 0.66196524, 0.82380099, 0.77739482],
[0.0431448 , 0.47664036, 0.80188153, 0.8099637 , 0.65258638],
[0.84862179, 0.22976325, 0.03508076, 0.72360136, 0.76835819]])
>>> x3[x3 < .5] = 0
>>> x3
array([[0.50866152, 0.56821455, 0.88531855, 0. , 0. ],
[0.96215686, 0. , 0. , 0. , 0.74759719],
[0. , 0.54718917, 0.66196524, 0.82380099, 0.77739482],
[0. , 0. , 0.80188153, 0.8099637 , 0.65258638],
[0.84862179, 0. , 0. , 0.72360136, 0.76835819]])
眼眸繁星
TA貢獻(xiàn)1873條經(jīng)驗(yàn) 獲得超9個(gè)贊
僅針對(duì)枚舉和三元條件介紹，您可以執(zhí)行以下操作：
import numpy as np
x = 5
y = 5
x3 = np.random.rand(x,y)
def choice(arr):
for row_idx, row in enumerate(arr):
for col_idx, val in enumerate(row) :
arr[row_idx,col_idx] = val if val >= 0.5 else 0
return arr
y3 = choice(x3.copy())
但是 AKX 解決方案更好。
添加回答
舉報(bào)
0/150
提交
取消