首頁(yè) 猿問(wèn) 求高手幫助，為什么會(huì)出現(xiàn)butte...

求高手幫助，為什么會(huì)出現(xiàn)butter函數(shù)的問(wèn)題，怎么解決？求大俠指點(diǎn)！

數(shù)學(xué)

天涯盡頭無(wú)女友 2023-04-20 19:15:59

寫(xiě)好的程序運(yùn)行時(shí)出現(xiàn)如下錯(cuò)誤，??? Undefined function or method 'butter' for input arguments of type 'double'.Error in ==> Shot_time_cross_zero_rate at 4[b,a]=butter(4,[0.025 0.85]);%4階巴特沃斯濾波器，上下截止頻率100Hz，3400Hz程序前4行如下clear allclose all[x,fs,bit]=wavread('F:\test.wav');[b,a]=butter(4,[0.025 0.85]);%4階巴特沃斯濾波器，上下截止頻率100Hz，3400Hz

查看完整描述

2 回答

慕的地6264312

TA貢獻(xiàn)1817條經(jīng)驗(yàn) 獲得超6個(gè)贊

從錯(cuò)誤提示來(lái)看，應(yīng)該是傳遞給butter函數(shù)的實(shí)參錯(cuò)誤。
從樓主的調(diào)用來(lái)看應(yīng)該是下面這三種情況：
應(yīng)該是少了一個(gè)參數(shù)，導(dǎo)致報(bào)錯(cuò)。

If Wn is a two-element vector, Wn = [W1 W2], butter returns an
order 2N bandpass filter with passband W1 < W < W2.
[B,A] = butter(N,Wn,'high') designs a highpass filter.
[B,A] = butter(N,Wn,'low') designs a lowpass filter.
[B,A] = butter(N,Wn,'stop') is a bandstop filter if Wn = [W1 W2].