public class TestDeadLock{ static Object O1 = new Object (); static Object O2 = new Object (); public static void main(String args[]){ Runner6 T1 = new Runner6(); Runner6 T2 = new Runner6(); T1.flag = false; T1.start(); T2.start(); } } class Runner6 extends Thread{ public boolean flag = true; public void run(){ if(flag){ synchronized(TestDeadLock.O1){ System.out.println("O1鎖住了"); try{sleep(1000);}catch(InterruptedException e){} } synchronized(TestDeadLock.O2){ System.out.println("2"); } } else{ synchronized(TestDeadLock.O2){ System.out.println("O2鎖住了"); try{sleep(1000);}catch(InterruptedException e){ } } synchronized(TestDeadLock.O1){ System.out.println("1"); } } } }
2 回答
繁星點(diǎn)點(diǎn)滴滴
TA貢獻(xiàn)1803條經(jīng)驗(yàn) 獲得超3個贊
最簡單了 你把每個synchronized里面都加個相應(yīng)的
TestDeadLock.O2.wait()或者TestDeadLock.O1.wait()就行了
眼眸繁星
TA貢獻(xiàn)1873條經(jīng)驗(yàn) 獲得超9個贊
給你一個例子：
package cn.com.io.threadDemo.ThreadSyn;
/**
* 通過兩個屬性值創(chuàng)建死鎖
* 本程序通過兩個線程各自鎖定一個屬性值，這樣兩個線程都無法結(jié)束，造成死鎖
* @author Administrator
*
*/
public class ThreadSyn2 implements Runnable{
private static Object obj1=new Object();
private static Object obj2=new Object();
/**
* @param args
*/
public static void main(String[] args) {
ThreadSyn2 ts1=new ThreadSyn2();
ThreadSyn2 ts2=new ThreadSyn2();
Thread t1=new Thread(ts1);//線程1
Thread t2=new Thread(ts2);//線程2
t1.setName("theOne");
t2.setName("theTwo");
t1.start();
t2.start();
}
public void run() {
String name=Thread.currentThread().getName();
if(name.equals("theOne")){
method1(name);
}else{
method2(name);
}
}
//線程1的方法鎖定obj1，線程2就無法完成
private void method1(String name) {
System.out.println(name);
synchronized(obj1){
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
synchronized(obj2){
System.out.println(obj2);
}
}
}
//線程1的方法鎖定obj2，線程1就無法完成
private void method2(String name) {
System.out.println(name);
synchronized(obj2){
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
synchronized(obj1){
System.out.println(obj1);
}
}
}
}
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