我快要瘋了。鑒于我有 2 個數(shù)組$array1 = [ "data_to_merge" => ["2020-03-11 16:00:00", "2020-03-24 14:00:00"], "data_to_merge_past_year" => ["2019-03-11 16:00:00"],];$array2 = [ "data_to_merge" => [], "data_to_merge_past_year" => ["2018-03-11 14:00:00"],];我的目標(biāo)是得到這樣的結(jié)果all: [ "data_to_merge" => [ "2020-03-11 16:00:00", "2020-03-24 14:00:00" ], "data_to_merge_past_year" => [ "2018-03-11 14:00:00", "2018-03-11 16:00:00", ], ],我試過簡單的$result = collect($array1)->merge(collect($array2));但是通過這種方法，它將從我的第一個數(shù)組中刪除值data_to_merge。有什么 Laravel 方法可以得到那個結(jié)果嗎？它可以超過 2 個數(shù)組，只是為了演示。這是我的完整示例，基本上是一樣的$array1 = [ "host" => "blablubb", "data_to_merge" => [ "2020-03-11 16:00:00", "2020-03-24 14:00:00" ], "data_to_merge_past_year" => [ "2019-03-11 16:00:00" ],];$array2 = [ "host" => "blablubb", "data_to_merge" => [], "data_to_merge_past_year" => [ "2018-03-11 16:00:00" ],];$array3 = [ "host" => "blablubb", "data_to_merge" => [], "data_to_merge_past_year" => [],];$array4 = [ "host" => "blablubb", "data_to_merge" => [ "2020-03-04 14:00:00", "2020-03-04 17:00:00" ], "data_to_merge_past_year" => [],];$all = collect([$array1, $array2, $array3, $array4]);$all ->groupBy('host') ->map(function ($item) { if (count($item) > 1) { $result = collect([]); foreach ($item as $subItem) { $result = $result->merge($subItem); } return $result; } return $item->first(); }) ->values() ->toArray();多謝你們！
1 回答
藍(lán)山帝景
TA貢獻(xiàn)1843條經(jīng)驗 獲得超7個贊
您可以為此使用mergeRecursive ：
$array1 = [
? ? "data_to_merge" => ["2020-03-11 16:00:00", "2020-03-24 14:00:00"],
? ? "data_to_merge_past_year" => ["2019-03-11 16:00:00"],
];
$array2 = [
? ? "data_to_merge" => [],
? ? "data_to_merge_past_year" => ["2018-03-11 14:00:00"],
];
$result = collect($array1)->mergeRecursive(collect($array2));
結(jié)果：
Illuminate\Support\Collection {#1278 ▼
? #items: array:2 [▼
? ? "data_to_merge" => array:2 [▼
? ? ? 0 => "2020-03-11 16:00:00"
? ? ? 1 => "2020-03-24 14:00:00"
? ? ]
? ? "data_to_merge_past_year" => array:2 [▼
? ? ? 0 => "2019-03-11 16:00:00"
? ? ? 1 => "2018-03-11 14:00:00"
? ? ]
? ]
}
從文檔：
mergeRecursive 方法將給定的數(shù)組或集合遞歸地與原始集合合并。如果給定項中的字符串鍵與原始集合中的字符串鍵匹配，則這些鍵的值將合并到一個數(shù)組中，這是遞歸完成的：
$collection = collect(['product_id' => 1, 'price' => 100]);
$merged = $collection->mergeRecursive(['product_id' => 2, 'price' => 200, 'discount' => false]);
$merged->all();
// ['product_id' => [1, 2], 'price' => [100, 200], 'discount' => false]
- 1 回答
- 0 關(guān)注
- 151 瀏覽
添加回答
舉報
0/150
提交
取消