我的問(wèn)題是我想要一個(gè)跟蹤器來(lái)跟蹤一個(gè)句子發(fā)送了多少次以及我何時(shí)運(yùn)行：from tkinter import *from pynput.keyboard import Key, Controllerimport timeroot = Tk()messages = 0root.geometry('500x1400')def startn(): global messages global label message = "Read the Channel" spam = int(input('How many sentences will you send?')) for num in range(0, int((spam))): messages = int(messages + 1) label = Label(root, text= messages) label.pack() root.mainloop() startn()每當(dāng)我在 label.pack() 之后添加 .destroy 時(shí)，它都不會(huì)顯示任何內(nèi)容（順便說(shuō)一句，spam = 5）在 label.pack() 之后輸出帶 .destroy 輸出不帶 .destroy
1 回答
拉丁的傳說(shuō)
TA貢獻(xiàn)1789條經(jīng)驗(yàn) 獲得超8個(gè)贊
下面的代碼應(yīng)該做你想做的。無(wú)需破壞標(biāo)簽，您只需使用 .configure() 方法重新配置相同的標(biāo)簽即可。我懷疑你真正想要的方法是 .pack_forget() 所以我也包含了它。我沒(méi)有運(yùn)行這段代碼，所以如果您有任何問(wèn)題，請(qǐng)發(fā)表評(píng)論，以便我進(jìn)行更正。
from tkinter import *
from pynput.keyboard import Key, Controller
import time
root = Tk()
messages = 0
label = Label(root) # create your widgets early
root.geometry('500x1400')
def startn():
global messages
global label
message = "Read the Channel"
spam = int(input('How many sentences will you send?'))
label.pack() # only need to pack it once
for num in range(0, int((spam))):
messages = int(messages + 1)
label.configure(text= messages) # you should configure instead of making new label
def stopn():
label.pack_forget() # the label reference still exists, but it is no longer packed. You can destroy the label, but I just leave it for the garbage collector.
startn()
root.after(10000, stopn) # will run stopn callback after 10 seconds
root.mainloop() # in my opinion should always be at the end.
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