我有初始代碼：books = []def add_book(): name = input('Input the name of the book: ') author = input('Input the author: ') print('Book added successfully.') books.append( { 'name': name, 'author': author, 'read': False } )我需要用戶能夠提供書名，如果他的輸入匹配中的名稱books，則刪除其引用的整個字典。我想出了這段代碼：def delete_book(): user_input = input('Input the name of the book to be deleted: ') for book in books: for key, value in book.items(): if book['name'] == user_input: books.remove(book)但它不起作用..我瀏覽了大約 2 個小時來找到解決方案，作為初學者我無法弄清楚，也許你們可以讓我清醒一下。read現(xiàn)在再看一下字典中的鍵值。我希望用戶能夠將值更改為 True。所以我嘗試了很多版本，但這更難。這就是我所擁有的：def mark_read(): # TODO REVIEW !!!! book_name = input('Input name of the book: ') for book in books: if book == book_name: user_input = input('Mark book as read? (y/N): ') if user_input == 'N' or 'n': print('No changes were made') elif user_input == 'Y' or 'y': book.update(read=True) else: print('The specified book is not currently in our database.')那么你能告訴我我錯在哪里給我一個更好但新手可讀的選擇嗎？
2 回答
瀟瀟雨雨
TA貢獻1833條經(jīng)驗 獲得超4個贊
刪除代碼：
def delete_book():
user_input = input('Input the name of the book to be deleted: ')
for i,book in enumerate(books):
if book['name'] == user_input:
del books[i]
標記為已讀的代碼：
def mark_read(): # TODO REVIEW !!!!
book_name = input('Input name of the book: ')
f=0 #flag to see if book is present in dict
for book in books:
if book['name'] == book_name:
f=1
user_input = input('Mark book as read? (y/N): ')
if user_input == 'N' or 'n':
print('No changes were made')
elif user_input == 'Y' or 'y':
book['read']=True
break #if book is found, you can exit the loop early
if f==0:
print('The specified book is not currently in our database.')
呼啦一陣風
TA貢獻1802條經(jīng)驗 獲得超6個贊
您的代碼的問題在于，當您只需要一個字段 () 時，您正在循環(huán)字典name。因此，您正在刪除具有字典第一個字段的書，但您試圖再次刪除具有字典下一個字段的條目，這是不可能的。
您不需要遍歷字典的所有字段來只比較一個字段。以下作品：
books =[{'name': "Hello", "author": "Arthur"}, {'name': "Hi", "author": "Vicky"}]
user_input = input('Input the name of the book to be deleted: ')
for book in books:
if book['name'] == user_input:
books.remove(book)
print(books)
輸入“Hi”時的結果：
[{'name': 'Hello', 'author': 'Arthur'}]
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