這是我第一次使用 json。是這樣的情況：我通過 php 從我的 mysql 數(shù)據(jù)庫獲取數(shù)據(jù)并將其存儲到 php 數(shù)組中：$statement = $mysqli->prepare("SELECT chatToken, lastMessageID FROM chat")$statement->execute();$result = $statement->get_result();while($row = $result->fetch_object()) { $chatData[$row->chatToken] = $row->lastMessageID;}現(xiàn)在我想在 jquery 函數(shù)中得到它：我試過這個：var chatData = '<? echo json_encode($chatData); ?>'myFunction(chatData) function myFunction(chatData) { console.log(chatData) // OUTPUT: {"tgv5pxfjsDGXA3JcEYVM":88,"a9gxNZ7HzfcJXQsWCtAp":99} $.ajax({ type: "POST", url: "getData.php", data: 'chatData='+chatData, dataType: 'json', }).done(function(result) { console.log(result); // Please look the Picture below for output }) }console.log(result) 的輸出獲取數(shù)據(jù).php<?php$chatData = json_decode($_POST['chatData']);$message = array();foreach($chatData AS $chatToken => $lastMessageID) { $statement = $mysqli->prepare("SELECT * FROM `messages` WHERE `chatToken` = ? AND `ID` > ?") $statement->bind_param("ss", $chatToken, $lastMessageID); $statement->execute(); $result = $statement->get_result(); while($row = $result->fetch_object()) { $message[] = array( "lastMessageID" => $row->ID, "chatToken" => $row->chatToken, ); } $statement->close();}echo json_encode($message);?>到目前為止，一切都很好。但現(xiàn)在我想替換/更新我的var chatData：{"tgv5pxfjsDGXA3JcEYVM":88,"a9gxNZ7HzfcJXQsWCtAp":99}的值來自result. 最后它必須是：{"tgv5pxfjsDGXA3JcEYVM":188,"a9gxNZ7HzfcJXQsWCtAp":99}我怎樣才能意識到呢？
1 回答
GCT1015
TA貢獻(xiàn)1827條經(jīng)驗(yàn) 獲得超4個贊
由于 chatData 是 JSON（字符串），您可以：
解析成一個對象
JSON.parse做出改變
將其轉(zhuǎn)換回字符串
JSON.stringify
// result from ajax call, jquery converts this from the php json to an object/array
var result = [{chatToken:"tgv5pxfjsDGXA3JcEYVM",lastMessageID:188}];
// string from `var chatData = <?php ...` as JSON
var chatData = '{"tgv5pxfjsDGXA3JcEYVM":88,"a9gxNZ7HzfcJXQsWCtAp":99}';
// convert string to object
var data=JSON.parse(chatData);
// use the first result array ([0]) chatToken to update chatData
data[result[0].chatToken] = result[0].lastMessageID;
// convert back to JSON (string)
chatData = JSON.stringify(data);
// show result
console.log(chatData);
在你的情況下，我建議chatData在開始時轉(zhuǎn)換為一個對象
var chatData = JSON.parse('<? echo json_encode($chatData); ?>');然后將其用作對象，然后僅在需要時轉(zhuǎn)換為 json(string)（在 ajax 帖子中）
data: 'chatData='+JSON.stringify(chatData),
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