我正在嘗試按升序和降序?qū)?shù)字?jǐn)?shù)組進(jìn)行排序。我是初學(xué)者，所以使用以下鏈接Sort an array in Java。我正在嘗試從用戶那里獲取輸入作為數(shù)組的元素。public class SortingofString {public static void main(String[] args) { Scanner input=new Scanner(System.in); int Array1[]; // String Array2[]; System.out.println("How many numaric elements: "); int n = input.nextInt(); int[] array1 = new int[n]; int number=input.nextInt(); for(int i=0; i<n; i++){ System.out.println("Enter number:"); array1[i] = number; System.out.println("Original numeric array : "+Arrays.toString(Array1)); Arrays.sort(Array1); System.out.println("Sorted numeric array : "+Arrays.toString(Array1)); } }}Array1當(dāng)我在第一個(gè)函數(shù)中傳遞我的 array_name 時(shí)發(fā)生錯(cuò)誤toString。System.out.println("Original numeric array : "+Arrays.toString(Array1));錯(cuò)誤說(shuō)Initialize variable Array1。我該如何解決這個(gè)錯(cuò)誤？
2 回答
胡子哥哥
TA貢獻(xiàn)1825條經(jīng)驗(yàn) 獲得超6個(gè)贊
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
//int Array1[];
System.out.println("How many numaric elements: ");
int n = input.nextInt();
int arr[] = new int[n];// solve 1st problem
for (int i = 0; i < n; i++) {
System.out.println("Enter number: " +(i+1));
int number = input.nextInt();
arr[i]=number;//init array by user input data
}
System.out.println("Original numeric array : " + Arrays.toString(arr));
Arrays.sort(arr);
System.out.println("Sorted numeric array : " + Arrays.toString(arr));
}
你還需要 2 導(dǎo)入
import java.util.Arrays;
import java.util.Scanner;
揚(yáng)帆大魚
TA貢獻(xiàn)1799條經(jīng)驗(yàn) 獲得超9個(gè)贊
Array1在 reading 后面移動(dòng)（并重命名）n：
System.out.println("How many numaric elements: ");
int n = input.nextInt();
int[] array1 = new int[n];
也許使用輸入的number：
int number = input.nextInt();
array1[i] = number;
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