我有一輛車，我想向左/向右/向上/向下移動，但也要沿對角線移動。前四個(gè)效果很好，但是當(dāng)我讓它沿對角線移動時(shí)，圖像并沒有改變。keys = pg.key.get_pressed()if keys[pg.K_LEFT] or keys[pg.K_q]: van.state = VAN_LEFT screen.acceleration.x = screen.vitesseif keys[pg.K_UP] or keys[pg.K_z]: van.state = VAN_UP screen.acceleration.y = screen.vitesseif (keys[pg.K_LEFT] or keys[pg.K_q]) and (keys[pg.K_UP] or keys[pg.K_z]): van.state = VAN_LEFT_UP screen.acceleration.x = screen.vitesse screen.acceleration.y = screen.vitesse如果我在主循環(huán)中添加print(van.state)，它永遠(yuǎn)不會是 van_left_up。有誰知道我做錯了什么？
2 回答
桃花長相依
TA貢獻(xiàn)1860條經(jīng)驗(yàn) 獲得超8個(gè)贊
我終于找到了如何讓它工作。這可能不是最好的解決方案，但它完全符合我的要求。相反，或者只有if keys[pygame.K_UP]and if keys[pygame.K_LEFT]，我這樣寫：
if keys[pygame.K_UP] and not keys[pygame.K_LEFT]:
...
if keys[pygame.K_LEFT] and not keys[pygame.K_UP]:
...
if keys[pygame.K_LEFT] and keys[pygame.K_UP]:
...
所以它知道我當(dāng)時(shí)按下了兩個(gè)鍵。感謝那些試圖幫助我的人！
PIPIONE
TA貢獻(xiàn)1829條經(jīng)驗(yàn) 獲得超9個(gè)贊
根據(jù)評論討論，這段代碼應(yīng)該可以工作。首先檢查是否按下了兩個(gè)鍵，然后檢查是否按下了各個(gè)鍵。
keys = pg.key.get_pressed()
if (keys[pg.K_LEFT] or keys[pg.K_q]) and (keys[pg.K_UP] or keys[pg.K_z]):
van.state = VAN_LEFT_UP
screen.acceleration.x = screen.vitesse
screen.acceleration.y = screen.vitesse
elif keys[pg.K_LEFT] or keys[pg.K_q]:
van.state = VAN_LEFT
screen.acceleration.x = screen.vitesse
elif keys[pg.K_UP] or keys[pg.K_z]:
van.state = VAN_UP
screen.acceleration.y = screen.vitesse
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