我有一個(gè)數(shù)據(jù)存儲(chǔ)在數(shù)組中 $roles = [2,4];我想將我在 $roles 中的數(shù)據(jù)與數(shù)據(jù)庫(kù)中的數(shù)據(jù)進(jìn)行映射。如果我像上面那樣在 $roles 中有多個(gè)數(shù)據(jù)，我不知道如何映射數(shù)據(jù)，而且我不知道如何在表視圖中顯示所有數(shù)據(jù)。我試試這個(gè) if (count($roles) == 1) { if ($roles[0] == 2) { $data['need_app'] = $this->Hire_model->need_approval_req($OrganizationID, $requestor_id); }else if ($roles[0] == 3) { $data['need_app'] = $this->Hire_model->need_approval_recruiter(); }else if ($roles[0] == 4) { $data['need_app']=$this->Hire_model->need_approval_hr(); }else if ($roles[0] == 5) { $data['need_app'] = $this->Hire_model->need_approval_cc($PositionID, $OrganizationID, $requestor_id); }}else{ for ($i=0; $i < count($roles)-1 ; $i++) { if ($roles[0] == 2) { $data['need_app'] = $this->Hire_model->need_approval_req($OrganizationID, $requestor_id); var_dump(count($data['need_app'])); }else if ($roles[0] == 3) { $data['need_app'] = $this->Hire_model->need_approval_recruiter(); }else if ($roles[0] == 4) { $data['need_app']=$this->Hire_model->need_approval_hr(); }else if ($roles[0] == 5) { $data['need_app'] = $this->Hire_model->need_approval_cc($PositionID, $OrganizationID, $requestor_id); var_dump(count($data['need_app'])); } // var_dump(count($data['need_app'])); }}希望有人能幫助我
2 回答
翻翻過去那場(chǎng)雪
TA貢獻(xiàn)2065條經(jīng)驗(yàn) 獲得超14個(gè)贊
我寫了一段代碼可以幫助你解決這個(gè)問題，必要時(shí)會(huì)提到注釋。希望對(duì)你有幫助。
foreach ($roles as $role) {
if ($role == 2) {
$data['need_app'][] = $this->Hire_model->need_approval_req($OrganizationID, $requestor_id); // you need to make an array here otherwise the current value will over-write the previous one
var_dump(count($data['need_app']));
}else if ($role == 3) {
$data['need_app'][] = $this->Hire_model->need_approval_recruiter(); // you need to make an array here otherwise the current value will over-write the previous one
}else if ($role == 4) {
$data['need_app'][] =$this->Hire_model->need_approval_hr(); // ...
}else if ($role == 5) {
$data['need_app'][] = $this->Hire_model->need_approval_cc($PositionID, $OrganizationID, $requestor_id); // ...
}
// var_dump($data['need_app']);
}
元芳怎么了
TA貢獻(xiàn)1798條經(jīng)驗(yàn) 獲得超7個(gè)贊
foreach ($roles as $role) {
if ($role == 2) {
//your logic here
} else if ($role == 4) {
//your logic here
} else if ($role == WHAT_EVER_YOU_WANTS) {
//Logic
}
//your logic here
}
所以根據(jù)你的問題
foreach ($roles as $role) {
if ($role == 2) {
$data['need_app'] = $this->Hire_model->need_approval_req($OrganizationID, $requestor_id);
} else if ($role == 3) {
$data['need_app'] = $this->Hire_model->need_approval_recruiter();
} else if ($role == 4) {
$data['need_app'] = $this->Hire_model->need_approval_hr();
} else if ($role == 5) {
$data['need_app'] = $this->Hire_model->need_approval_cc($PositionID, $OrganizationID, $requestor_id);
}
}
而不是使用類似$role == 4
在函數(shù)內(nèi)創(chuàng)建一個(gè)常量或另一個(gè)變量，并使用該變量值循環(huán)條件。這對(duì)以后的修改很有幫助。
像這樣的東西
$loopValues = [1,2,3,4,5,6] // Or $loopValues = [['val' => 1, 'function' => functionName()]] <- I prefer this one all the time
然后像下面這樣循環(huán)
foreach ($roles as $role) {
if ($role == $loopValues[0]) {
//your logic here
}
}
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