我寫了這個 python 函數(shù)：d ={'key1':{'key2':{'key11':{'key12':'value13'}}},'key3':[{'key4':'value2', 'key5': 'value3'}]}key_path = 'key1.key2.key11.key12'def recursive_search(d, key_path): key_parts = key_path.split('.') if len(key_parts) == 1: return d.get(key_parts[0]) elif isinstance(d.get(key_parts[0]), dict): recursive_search(d.get(key_parts[0]), '.'.join(key_parts[1:])) elif isinstance(d.get(key_parts[0]), list): for i in d.get(key_parts[0]): for key in i.keys(): if key == key_parts[1]: recursive_search(i, '.'.join(key_parts[1:]))x = recursive_search(d, 'key3.key4')我期待返回“value2”，但沒有返回任何內容。我究竟做錯了什么？
1 回答
猛跑小豬
TA貢獻1858條經(jīng)驗 獲得超8個贊
當你遞歸調用時，你不會返回任何東西recursive_search。添加return，它會工作正常
d ={'key1':{'key2':{'key11':{'key12':'value13'}}},'key3':[{'key4':'value2', 'key5': 'value3'}]}
key_path = 'key1.key2.key11.key12'
def recursive_search(d, key_path):
key_parts = key_path.split('.')
if len(key_parts) == 1:
return d.get(key_parts[0])
elif isinstance(d.get(key_parts[0]), dict):
return recursive_search(d.get(key_parts[0]), '.'.join(key_parts[1:]))
elif isinstance(d.get(key_parts[0]), list):
for i in d.get(key_parts[0]):
for key in i.keys():
if key == key_parts[1]:
return recursive_search(i, '.'.join(key_parts[1:]))
x = recursive_search(d, 'key3.key4')
print (x)
輸出
value2
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