我有 2 個(gè) javascript 數(shù)組：const arr1 = ['one', 'two', 'three', 'four', 'five', 'six'];const arr2 = ['five', 'six', 'four', 'three', 'one', 'two'];PS-我無法更改/控制“arr1”的順序我的問題是如何使“arr2”的項(xiàng)目順序與“arr1”的項(xiàng)目相匹配。我一直在想它可能看起來像：//1. Some kind of function to get index of all itemsconst items = (item) => item === item; const arr3 = arr1.findIndex(items);//2. Then think I need to get the values of arr2 using ([Array.values()][1])**const arr2vals = arr2.values();//3. Then some kind of calculation that matches the values, this is where I really struggle more, but weak at best lol!arr3.filter(value => arr2vals.includes(value))** 參考：MDN