我有一個問題，我找不到解決方案。我正在嘗試過濾我的 javafx8 tableview，但我遇到了問題。我不知道如何只顯示兩個時間戳之間存在的數(shù)據(jù)。編輯：明確地說，我想知道如何使用文本字段為行配置開始和結(jié)束PS：我的tableview截圖：我已經(jīng)看過https://code.makery.ch/blog/javafx-8-tableview-sorting-filtering/。我在創(chuàng)建適當?shù)?時遇到了麻煩Predicate，他們在 tuto 中向您展示了如何僅顯示具有相同信息的信息。我想顯示兩者之間存在的信息。PS：項目類型是時間戳
1 回答
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TA貢獻1802條經(jīng)驗 獲得超5個贊
confirmdatebtn1.setOnAction(new EventHandler<ActionEvent>(){
@Override public void handle(ActionEvent e) {
filterData.setPredicate(table -> {
if ((todatetxt.getText() == null &&fromdatetxt.getText() == null) ||
(todatetxt.getText().isEmpty()&&fromdatetxt.getText().isEmpty()) ) {
return true;}
try {
String fromtext = fromdatetxt.getText();
String totext = todatetxt.getText();
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSS");
Date date1 = null;
Date date2 = null;
Timestamp timestamp1 = null;
Timestamp timestamp2 = null;
if(todatetxt.getText().isEmpty() && !fromdatetxt.getText().isEmpty()) {
date1 = format.parse(fromtext+" 00:00:00.000");
timestamp1 = new java.sql.Timestamp(date1.getTime());
if (table.getTime_of_action().after(timestamp1) )
{return true;}
}
if(!todatetxt.getText().isEmpty() && fromdatetxt.getText().isEmpty()) {
date2 = format.parse(totext+" 23:59:59.000");
timestamp2 = new java.sql.Timestamp(date2.getTime());
if (table.getTime_of_action().before(timestamp2) )
{return true;}
}
if(!todatetxt.getText().isEmpty() && !fromdatetxt.getText().isEmpty()) {
date1 = format.parse(fromtext+" 00:00:00.000");
date2 = format.parse(totext+" 23:59:59.999");
timestamp1 = new java.sql.Timestamp(date1.getTime());
timestamp2 = new java.sql.Timestamp(date2.getTime());
if (table.getTime_of_action().before(timestamp2) &&table.getTime_of_action().after(timestamp1))
{return true;}
}
} catch (Exception e1) {
}
return false;
});} });*** i wrote this code and it came out good so my probleme is resolved thanks to your help guys***
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