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我有一個dll文件叫GetNum.dll，里面有個命令GetNum，怎樣輸出這個命令的結(jié)果？

C 算法與數(shù)據(jù)結(jié)構(gòu)

米脂 2023-03-18 14:10:28

#include <WINDOWS.H> #include <WINBASE.H>typedef void (*MYPROC)(char*); void main(){HINSTANCE LibHandle;MYPROC ProcAdd; char sysbuf[] = "GetNum"; /*過程名*/LibHandle = LoadLibrary("GetNum.dll"); /*載入dll*/ ProcAdd = (MYPROC)GetProcAddress( LibHandle, sysbuf); /*獲取函數(shù)sysbuf的地址*/}

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2 回答

陪伴而非守候

TA貢獻1757條經(jīng)驗獲得超8個贊

GetNum.dll只是一個鏈接庫，，你只能調(diào)用接口函數(shù)?？磥砟氵€不懂怎么調(diào)用動態(tài)鏈接庫

反對回復(fù) 2023-03-21

料青山看我應(yīng)如是

TA貢獻1772條經(jīng)驗獲得超8個贊

根據(jù)我的猜測,有兩種情況1.如果 void GetNum(char* s);是把輸入的字符儲存在 *s中的話:#include <WINDOWS.H> #include <WINBASE.H>#include <stdio.h> typedef void (*MYPROC)(char*); /* 這里要與GetNum的返回值和參數(shù) 對應(yīng) */void main(){ HINSTANCE LibHandle; MYPROC ProcAdd; char ch; char sysbuf[] = "GetNum"; /*過程名*/ LibHandle = LoadLibrary("GetNum.dll"); /*載入dll*/ ProcAdd = (MYPROC)GetProcAddress( LibHandle, sysbuf); /*獲取函數(shù)sysbuf的地址*/ ProcAdd(&ch); printf("%c\n",ch);}

2.如果你的GetNum是int GetNum(char* s){ int i=0,ans=0; while(s[i]>='0'&&s[i]<='9') { ans=s[i]-'0'+ans*10; } return ans;} #include <WINDOWS.H> #include <WINBASE.H>#include <stdio.h> typedef int (*MYPROC)(char*); /* 改 */void main(){ HINSTANCE LibHandle; MYPROC ProcAdd; char s[100]; /* 改 */ char sysbuf[] = "GetNum"; /*過程名*/ LibHandle = LoadLibrary("GetNum.dll"); /*載入dll*/ ProcAdd = (MYPROC)GetProcAddress( LibHandle, sysbuf); /*獲取函數(shù)sysbuf的地址*/ scanf("%s",s); /* 改 */ printf("%d\n", ProcAdd(&s) ); /* 這里調(diào)用并輸出結(jié)果 */}