首頁(yè) 猿問(wèn) 如何分隔數(shù)組并將其放入括號(hào)中

如何分隔數(shù)組并將其放入括號(hào)中

JavaScript

30秒到達(dá)戰(zhàn)場(chǎng) 2023-03-18 16:53:54

我有一個(gè)數(shù)組（Geojson 文件），我想將它分成三個(gè)數(shù)組。有一些多邊形坐標(biāo)，我想為每個(gè) id 放置連續(xù)的坐標(biāo)，我想得到： arrGeo = [ [-4.66478, 58.42441, 5127.4,-4.65982, 58.42082, 5074.7], [-3.94815, 57.71632, 5000,-3.94812, 57.71576, 4374.1,-3.94216, 57.71541, 4283,-3.93717, 57.71583, 5001], [-3.93224, 57.71476, 4048,-3.93261, 57.71456, 3800.4] ]我嘗試通過(guò)使用 for 循環(huán)來(lái)做到這一點(diǎn)，但我無(wú)法將它們分開(kāi)，我的意思是我需要為每個(gè) ID 創(chuàng)建單獨(dú)的坐標(biāo)數(shù)組。我的代碼有什么問(wèn)題？我應(yīng)該怎么做才能解決它？這是我的代碼：positions = [ { "type": "Feature", "geometry": { "type": "GeometryCollection", "geometries": [ { "type": "Polygon", "coordinates": [ [ [-4.66478, 58.42441, 5127.4], [-4.65982, 58.42082, 5074.7], ] ] }, ] }, "id": "kml_1" }, { "type": "Feature", "geometry": { "type": "GeometryCollection", "geometries": [ { "type": "Polygon", "coordinates": [ [ [-3.94815, 57.71632, 5000], [-3.94812, 57.71576, 4374.1], ] ] }, { "type": "Polygon", "coordinates": [ [ [-3.94216, 57.71541, 4283], [-3.93717, 57.71583, 5001], ] ] }, ] }, "id": "kml_2" },

查看完整描述

4 回答

MMTTMM

TA貢獻(xiàn)1869條經(jīng)驗(yàn) 獲得超4個(gè)贊

let final = [];

for (var i = 0, len = positions.length; i < len; i++) {

? let a = [];

? for (var j = 0, jlen = positions[i]["geometry"]["geometries"].length; j < jlen; j++) {

? ??

? ? for (var k = 0, klen = positions[i]["geometry"]["geometries"][j]["coordinates"].length; k < klen; k++) {

? ??

? ? ? for (l = 0, llen = positions[i]["geometry"]["geometries"][j]["coordinates"][k].length; l < llen; l++) {

? ? ? ? a = a.concat(positions[i]["geometry"]["geometries"][j]["coordinates"][k][l]);

? ? ? }

? ? }

? }

? final.push(a);

}

console.log(final);

反對(duì) 回復(fù) 2023-03-18

SMILET

TA貢獻(xiàn)1796條經(jīng)驗(yàn) 獲得超4個(gè)贊

您可以使用 forEach 來(lái)實(shí)現(xiàn)，以獲得更好的性能。

let positions = [

{

type: "Feature",

geometry: {

type: "GeometryCollection",

geometries: [

{

type: "Polygon",

coordinates: [

[

[-4.66478, 58.42441, 5127.4],

[-4.65982, 58.42082, 5074.7],

],

},

],

},

id: "kml_1",

},

{

type: "Feature",

geometry: {

type: "GeometryCollection",

geometries: [

{

type: "Polygon",

coordinates: [

[

[-3.94815, 57.71632, 5000],

[-3.94812, 57.71576, 4374.1],

],

},

{

type: "Polygon",

coordinates: [

[

[-3.94216, 57.71541, 4283],

[-3.93717, 57.71583, 5001],

],

},

],

},

id: "kml_2",

},

{

type: "Feature",

geometry: {

type: "GeometryCollection",

geometries: [

{

type: "Polygon",

coordinates: [

[

[-3.93224, 57.71476, 4048],

[-3.93261, 57.71456, 3800.4],

],

},

],

},

id: "kml_3",

},

];

let newPolygons = []

const flatPositions = (arr)=>{

arr.forEach((pos)=>{

let p = []

pos?.geometry?.geometries.forEach((geometry)=>{

geometry?.coordinates.forEach(coord=>{

coord.forEach(coo=>{

p = p.concat(coo)

})

newPolygons.push(p)

})

}

flatPositions(positions)

console.log(newPolygons)

反對(duì) 回復(fù) 2023-03-18

嚕嚕噠

TA貢獻(xiàn)1784條經(jīng)驗(yàn) 獲得超7個(gè)贊

只需使用Array.prototype.reduce()
和Array.prototype.flat()
以及解構(gòu)賦值

const arrGeo = positions.reduce((a,{geometry})=>

? {

? let item = []

? for (let geo of geometry.geometries)

? ? {

? ? let p = geo.coordinates.reduce((t,c)=>

? ? ? {

? ? ? t.push(...c.flat())

? ? ? return t

? ? ? },[])

? ? ? item.push(...p)

? ? }

? a.push(item)

? return a

? },[])

完整代碼：

const positions =?

? ? ? [ { type: 'Feature'

? ? ? ? , geometry:?

? ? ? ? ? { type: 'GeometryCollection'

? ? ? ? ? , geometries:?

? ? ? ? ? ? [ { type: 'Polygon'

? ? ? ? ? ? ? , coordinates:?

? ? ? ? ? ? ? ? [ [ [ -4.66478, 58.42441, 5127.4]?

? ? ? ? ? ? ? ? ? , [ -4.65982, 58.42082, 5074.7]?

? ? ? ? ? ] ] } ] }?

? ? ? ? , id: 'kml_1'

? ? ? ? }?

? ? ? , { type: 'Feature'

? ? ? ? , geometry:?

? ? ? ? ? { type: 'GeometryCollection'

? ? ? ? ? , geometries:?

? ? ? ? ? ? [ { type: 'Polygon'

? ? ? ? ? ? ? , coordinates:?

? ? ? ? ? ? ? ? [ [ [ -3.94815, 57.71632, 5000? ?]?

? ? ? ? ? ? ? ? ? , [ -3.94812, 57.71576, 4374.1 ]?

? ? ? ? ? ? ? ] ] }?

? ? ? ? ? ? , { type: 'Polygon'

? ? ? ? ? ? ? , coordinates:?

? ? ? ? ? ? ? ? [ [ [ -3.94216, 57.71541, 4283]?

? ? ? ? ? ? ? ? ? , [ -3.93717, 57.71583, 5001]?

? ? ? ? ? ] ] } ] }?

? ? ? ? , id: 'kml_2'

? ? ? ? }?

? ? ? , { type: 'Feature'

? ? ? ? , geometry:?

? ? ? ? ? { type: 'GeometryCollection'

? ? ? ? ? , geometries:?

? ? ? ? ? ? [ { type: 'Polygon'

? ? ? ? ? ? ? , coordinates:?

? ? ? ? ? ? ? ? [ [ [ -3.93224, 57.71476, 4048]?

? ? ? ? ? ? ? ? ? , [ -3.93261, 57.71456, 3800.4]?

? ? ? ? ? ] ] } ] }?

? ? ? ? , id: 'kml_3'

? ? ? } ]?

const arrGeo = positions.reduce((a,{geometry})=>

? {

? let item = []

? for( let geo of geometry.geometries )

? ? {

? ? let p = geo.coordinates.reduce((t,c)=>

? ? ? {

? ? ? t.push(...c.flat())

? ? ? return t

? ? ? },[])

? ? ? item.push(...p)

? ? }

? a.push(item)

? return a

? },[])

arrGeo.forEach(el=> console.log(JSON.stringify(el)))

.as-console-wrapper { max-height: 100% !important; top: 0; }

反對(duì) 回復(fù) 2023-03-18

慕萊塢森

TA貢獻(xiàn)1810條經(jīng)驗(yàn) 獲得超4個(gè)贊

我不確定，但如果我理解正確，這應(yīng)該是理想的結(jié)果。我希望我有所幫助。

positions =

[

{

"type": "Feature",

"geometry": {

"type": "GeometryCollection",

"geometries": [

{

"type": "Polygon",

"coordinates": [

[

[-4.66478, 58.42441, 5127.4],

[-4.65982, 58.42082, 5074.7],

]

},

]

},

"id": "kml_1"

},

{

"type": "Feature",

"geometry": {

"type": "GeometryCollection",

"geometries": [

{

"type": "Polygon",

"coordinates": [

[

[-3.94815, 57.71632, 5000],

[-3.94812, 57.71576, 4374.1],

]

},

{

"type": "Polygon",

"coordinates": [

[

[-3.94216, 57.71541, 4283],

[-3.93717, 57.71583, 5001],

]

},

]

},

"id": "kml_2"

},

{

"type": "Feature",

"geometry": {

"type": "GeometryCollection",

"geometries": [

{

"type": "Polygon",

"coordinates": [

[

[-3.93224, 57.71476, 4048],

[-3.93261, 57.71456, 3800.4],

]

},

]

},

"id": "kml_3"

},

];

var arrGeo = [];

var res = [];

for (var i = 0; i < positions.length; i++) {

var x = positions[i].geometry.geometries;

var f = [];

for (var ii = 0; ii < x.length; ii++) {

var z = x[ii].coordinates[0];

var t = z.flat();

f.push(t)

}

res.push(f);

for (let ii = 0; ii < res.length; ii++) {

res[ii].flat();

}

for (var i = 0; i < res.length; i++) {

arrGeo.push(res[i].flat());

}

console.log(arrGeo);

反對(duì) 回復(fù) 2023-03-18

4 回答
0 關(guān)注
168 瀏覽

關(guān)注

添加回答

舉報(bào)

0/150

提交

取消

使用 Ctrl+D 可將網(wǎng)站添加到書(shū)簽

微信客服

購(gòu)課補(bǔ)貼
聯(lián)系客服咨詢優(yōu)惠詳情

幫助反饋 APP下載

慕課網(wǎng)APP
您的移動(dòng)學(xué)習(xí)伙伴

公眾號(hào)

掃描二維碼
關(guān)注慕課網(wǎng)微信公眾號(hào)

第七色在线视频,2021少妇久久久久久久久久,亚洲欧洲精品成人久久av18,亚洲国产精品特色大片观看完整版,孙宇晨将参加特朗普的晚宴

熱搜

最近搜索清空

如何分隔數(shù)組并將其放入括號(hào)中

如何分隔數(shù)組并將其放入括號(hào)中

4 回答

添加回答